<p>about 60 for a 5, 45 for a 4, 30 for a 3, 20 for a 2, 20- for a 1</p>
<p>this year everyone said that ap calculus bc exam was extremely easy.. with that said, a 60 would get you a 5???</p>
<p>i am pretty sure it cannot go above 70 for a 5 on BC and likie a 75 for ab.
I mean the test was not that easy.
Compared to last year it was easier (well i took AB last year), but still it was not a cake walk.
I am happy a lil cos bc curves are a lil better</p>
<p>for 4c wouldn't the speed be increasing because the acceleration is positive?</p>
<p>
[QUOTE]
for 4c wouldn't the speed be increasing because the acceleration is positive?
[/QUOTE]
</p>
<p>No, it's decreasing. Speed is the magnitude of velocity, so the negative sign doesn't matter. That is something they always ask about on the vectors questions, since they had no vectors question they asked about it on another one.</p>
<p>any idea what a composite score of 55 would be this year for bc exam?</p>
<p>^ a very safe 4.</p>
<p>really??? a composite score of 55 out of 108 would be a safe 4 on the calculus bc exam this year???</p>
<p>^ my bad. Maybe not "safe" 4, but pretty sure it would be a 4. Maybe a 3 if u get real unlucky.</p>
<p>sweet....
with all the answers....here is what i probably got</p>
<p>5,7,9,9,5,3= 38</p>
<p>and with my multiple choice.....pretty much sounds like a 5</p>
<p>a 55 is a verrry safe 4.....</p>
<p>ok, so i feel sort of stupid because it seems like this is a pretty easy problem...
but could anybody please explain how to do 6(c)? and 6(d)? i seriously have no idea how. i feel like i'm missing a really important concept. </p>
<p>also, 2(b)? you couldn't use the (b-a)/2h (y1+2y2...) etc. formula, right? then how do you do it? </p>
<p>thanks!!</p>
<p>so anyone think i'll be penalized for accidentally answering the integral on 1b?</p>
<p>i should probably be considering i didn't read it properly :/</p>
<p>but they wouldn't void the whole question right?</p>
<p>I don't believe so, Freezenthaw, but I suppose if the answer is wrong, they could in theory penalize you for it.</p>
<p>jersey_jazz, for 2(b), you can find the areas of each trapezoid individually, using the h(b-a)/2, where h varies for each value of h.</p>
<p>I haven't looked at 6, so I'll leave that one open.</p>
<p>You probably won't be penalized for answering it. I don't get the point of those questions if they're on a calculator section, really...</p>
<p>The reason has to do with the allocation of points. There are only 9 points available for the question, and usually, evaluating an integral is worth a point.</p>
<p>They must have thought that getting an answer for that integral would leave them with one point too many. :)</p>
<p>not to be a pain
but isnt the area of a trapezoid
(1/2)(b+a)h
not (1/2)(b-a)h like the math prof</p>
<p>That's what happens when I post at 11:16 PM. :) You're right.</p>
<p>for part 3a, i got 67.2 and for part 3b, i got 67.98622222... </p>
<p>almost positive that these answers are right</p>
<p>first-degree series = 80 + 128(x-2)</p>
<p>third-degree series = 80 + 128(x-2) + 244/3(x-2)^2 + 224/9(x-2)^3</p>
<p>^ crap i think i got those taylor series wrong
i wrote out the 1st and 3rd degree series correctly</p>
<p>but instead of adding 128(1.9-2) to 80, i must have left out the negative sign in the product of 128(-.1) so i ended up getting 92 instead of 68</p>
<p>=[</p>