<p>You don’t happen to have a site that has them in a non-pdf version do you? Cuz my computer is stupid and every time i try to download adobe reader it doesnt work.</p>
<p>Um, try putting the links in this site:
[Online</a> viewer for PDF, PostScript and Word](<a href=“http://view.samurajdata.se/]Online”>http://view.samurajdata.se/)
It should work.</p>
<p>Ok cool, works perfectly, thanks Malfunction.</p>
<p>You forgot this link</p>
<p>AP Calculus BC </p>
<p><a href=“Supporting Students from Day One to Exam Day – AP Central | College Board”>Supporting Students from Day One to Exam Day – AP Central | College Board;
<p>By the way, I took that one ^, question 6 was the ****…</p>
<p>anyone got the solutions? I just realized i messed up on the volume question lol</p>
<p>Ugh, I can’t edit it the OP now… Oh well, thanks for pointing that out.</p>
<p>Can someone please tell me how to do number 6 on AB form A?</p>
<p>@RC1992</p>
<p>which part of number six?
i didn’t take the Calc AB exam, but i just looked over it and i’m pretty sure i have the right answer to that one.</p>
<p>So, who wants to work out the BC problems so I don’t have to overexert my already-fried brain? ;)</p>
<p>
</p>
<p>So I know how poorly I did? Hell no</p>
<p>Haha it was worth a try.</p>
<p>what’s the answer to #6 AB?</p>
<p>Here are my AB answers. I’m too lazy to take out my caclulator and actually solve them though.</p>
<p>1.
a) integral from 0 to 6 of f(t)dt
b) I forget how I did this…
c) 0 + 125 + 108 + 108
d) integral from 0 to 9 of f(t)dt - answer for C</p>
<p>2.
a) (21-13)/(7-5)
b) I don’t feel like doing this one again.
c) 2300 - Integral from 8 to 12 of P(t)dt
d) Solve for p’(t) = 0</p>
<ol>
<li>I honestly think I screwed this whole FRQ up so I’m not even going to try.</li>
</ol>
<p>4.
a) integral from 0 to 9 of 6dx - integral from 0 to 9 of 2rad(x)dx
b) I just realized I did the disk method for this and not the washer. Crappppp.
c) Aaaand I realized I solved for y = rad(x) for this and not 2rad(x). *** was I thinking?</p>
<p>5.
a) g(3) = 10, g(-2) = 3
b) x = 0. It’s the only place on the derivative graph where there is a horizontal tangent at a differentiable point.
c) I drew a picture. Of a smiley face.</p>
<ol>
<li>
a) y - 2 = 8(x - 1)
b) y - 2 = 8(1.1 - 1). I had no idea how to tell if it was under or overestimated.
c) Don’t feel like doing this again.</li>
</ol>
<p>I think you screwed up your 5A…i got </p>
<p>5+ Pii +1.5</p>
<p>and 5-pii</p>
<p>
</p>
<p>Oh ****…I think I did the same lol, I have no idea what I was thinking either. A lot of pressure at that time.</p>
<p>I had absolutely no clue what the integral in 2b meant</p>
<p>I am not looking forward to going over every problem Monday morning in class</p>
<p>
</p>
<p>Average value for integrals</p>
<p>I don’t remember exactly what I got for 5a, but the g(3) definitely had a pi somewhere since part of it was the area of the semicircle…and g(-2) couldn’t have had pi in if it was just the area of the triangle…?</p>
<p>God I feel like a 3…I seriously ****ed up my test lol</p>
<p>g(-2) wasn’t the triangle.</p>