<p>Working123
Im pretty sure we’re right about the consecutive prob</p>
<p>Working 123 I am not sure… you can very well be right as to what they asked for. Can someone else weigh in??? If you are right, then your answer is the correct one</p>
<p>No because it didn’t specify that b was even so if b was odd it would be an odd exponent and when you have a negative exponent negatives stay negative ie -3^3=-27</p>
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<p>Haha, alright then. That makes me feel better.</p>
<p>Does anyone else agree on the a-b</p>
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<p>Ben, the possible choice was b^2a.
Absolute value of B is equal to A, B is just the opposite.
Using -3 for B, 3 would be A.
(-3)^2*3 is equal to (-3)^6 which is 729.</p>
<p>Benh10, it was 2b, and 2 times any number is going to be even.</p>
<p>benh10, you are wrong because the answer was b^2a. -3^2[3] = a really big positive number. The trick to this question was to know that by multiplying any number by two would make it an even integer</p>
<p>Wait for the |a| = |b| one, what was the answer?</p>
<p>Ah dang it</p>
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<p>Wait did it specify if a and b were integers?</p>
<p>b^2a.
I think it was D on the test…</p>
<p>It’s alright benh10, at least you put up a good fight</p>
<p>What if a and b = +/- 1.5?</p>
<p>-1.5^3 is negative</p>
<p>They have to be integers</p>
<p>well, if thats the case, then I screwed up.
I actually dont remember anything being said of a and b being integers.
Hmmm</p>
<p>@kongo It must have said that the numbers were integers. SO it could have only been 1,2,3,4,5…</p>
<p>No the problem specified integers</p>
<p>Wait is anyone 100% positive that it had to be an integer?</p>
<p>wasn’t it E? i know i put b^2a but i cant remember what that was</p>