@SippinCoffee - Hahaha, yeah…highly doubt the AP would ask about this anyway
@Mathman97 They provide an alternate pathway, but don’t worry about that, too in depth.
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STP (usually gases) is 0C (273K), 1 atm (now as 1bar per IUPAC) and 1 mole of ideal gas is 22.4 L.
Standard State (other than gases usually) is 25C, 1M pure substances, 1atm
@Mathman97 The rate constant is k, just k. The whole thing is the rate law. 
So for the 2014 practice test, what constitutes as a 3, 4, 5? Excuse me if this is a stupid question lol
*Note, I would suggest you to read Rate constant vs Equilibrium constant. A lot of people appear confused. Rate is altered easily. Equillibrium, not so much.
ALRIGHT THIS ENTIRE DISCUSSION ABOUT RATE CONSTANT IS COMPLETELY CONFUSING ME
Basically, the rate of dissolving a pill increases as it’s being crushed because you’re introducing more molecules, which is the same thing as increasing the concentration of the solute, which results in more collisions. This DOESN’T affect the rate constant; the rate only increases because concentration is increasing.
What’s this whole thing about surface area changing the rate constant in the case of a dissolved pill?
@Mathman97 1 x 2 = 2
1 x 4 = 4
1 is still equal to 1.
@APScholar18 At STP, temperature is 273K and pressure is 1 atm.
Does the identity of the ions in a salt bridge of a galvanic cell matter?
This thread is descending into chaos
OKAY PEOPLE:
Arrhenius equation: k=Ae−Ea/RT
Increasing surface area would increase A, increasing the rate constant. BUT, YOU CAN’T INCREASE THE SURFACE AREA OF A MOLECULE WITHOUT CHANGING THE MOLECULE ITSELF.
^Thank you
@glasshours
ok, changing sa means more collisions occur, meaning the rate increases, since concentration doesnt change, k would have to change
@kazoo98 Yes, negative ions go from the cathode to the anode. Positive particles go from the anode to the cathode.
This is done to balance the charge difference due to moving electrons.
@Frigidcold yes you can, crushing a pill is a physical, not chemical change which increases sa
@Mathman97
Changing the surface area would mean using different reactants, that’s why it doesn’t matter.
@Mathman97 Correct. You can think of it as, the higher you go, the less particles there are, and thus, less pressure.