can someone please explain 2014 #17?
@shough101 use hess’s law to find the 3rd equation
@Mathman97 Generally, up to a certain point, don’t think they would make you consider temp vs. altitude though
I think since the K1 and K2 combine to make K3, it’s greater than 1 and when K is greater than 1 it’s thermodynamically favored @shough101
@kenjaben: hahahaha im not stressing out no no im fine i just hate chem arghh im doooomed for this test…
I don;t think catalyst affect rate constant?
no just affects the rate of reaction @APScholar18
@APScholar18 hydrogen is the smallest of the atoms, so it has the shortest internuclear distance, n2 has triple bonds which is shorter than oxygen’s single bonds so it is ranked h2, n2, and o2
@APScholar18 This is a terrible answer, but if you read based on intermolecular distance, H2 smallest, N2 middle, O2 largest. That’s how I did it, got it right on a graded test. 
@Sippincoffee glass doors said it does
^What
@Frigidcold - In the case of a crushed pill, would the rate constant not change because you’re technically introducing more molecules to the solution and thus increasing the concentration?
Rate constant is affected by the following: Surface area, temperature, pressure, catalyst, concentration etc. Basically Everything.
What is affected by ONLY temperature is EQUILIBRIUM CONSTANT, defined as kf/kr
@frigidcold please explain #17 on 2014
@glasshours you would be changing the surface area in that case which would change the rate constant
@APScholar18 Lol, that’s the best explanation I can give, I just guessed when I did it based on intermolecular distance.
“Catalysts change the rate constant, but they only affect the kinetics (speed) of the reaction. They don’t alter any thermodynamic properties.”
Okay so yes the rate constant is affected by the catalyst, but only the temperature affects it thermodynamically
Honestly I don’t get it but I’m just going to run with it
@glasshours Don’t believe rate constant is affected by concentrations. 
KEavg is defined as 3kT with k as the boltzmann constant so yes. (R/n=k)
@SippinCoffee That’s what I’ve been trying to say.
TEMPERATURE IS THE ONLY THING YOU NEED TO CONSIDER FOR RATE CONSTANT.
so how do catalysts lower activation energy? they just increase the speed of the rxn?