<p>ugh…
now that I think of it, I think this test might ruin my straight 5s this year 
I doubt I got a 5 but, for sure a mid-high 4.</p>
<p>Does anyone else think the curve may be unusually forgiving this year? I don’t think I did a well enough job on this test to get a 5, but hopefully did good enough to get a 4.</p>
<p>well
I feel like as an underestimate i got 75% on the MC and i got around 45-55% on FRQs and supposedly from what I’ve heard that is still a low 5, but I don’t buy it. it seems too much of a curve!</p>
<p>@Maxgphysics94 - Yeah, it could go either way depending on the curve. Also depends on how your uncertain MC turned out, as well as partial credit on the FRQ.</p>
<p>I wouldn’t expect an unusually forgiving curve… look at some past forums. Everybody thinks that their year’s test is unusually difficult and expects a forgiving curve, but the curve doesn’t change much from year to year. Expect a 5 to be somewhere between 54-60 out of 90.</p>
<p>Guys, for the first mechanics FRQ where</p>
<p>W = 2*pi/T</p>
<p>I forgot the pi in the equation so my numbers are a bit off. How many points do you guys think I’ll lose?</p>
<p>Id guess only one because they shouldn’t count off for the same thing twice</p>
<p>Will I also lose another point because the angular frenquency (the w) will affect my x-max value in the x(t) function?</p>
<p>Also for the FRQ, how did you guys conduct your experiment?</p>
<p>I just used a table, ruler, and weight.</p>
<p>Drop the weight from a certain altitude (W=mgh), record the time it takes to hit the floor. Use those numbers to calculate the velocity to get the kinetic energy(W=0.5mv^2).</p>
<p>Semaphore, I did the same thing for the experiment. It was the first thing that popped in my head. I think I picked one additional tool from the list, because I remember checking off 4. Everyone else I talked to did a ramp, but they said that mine does test KE versus PE, so it should work. The only problem I ran into was explaining the last part. The final energy being too high could be from reaction time, as the trial only takes a few seconds. The last one needed it to be under, which can be attributed to air resistance, but that would also make the time higher, so I kind of ignored that. I was worried about that too, but I feel like it should make sense.</p>
<p>Did anyone notice a discrepancy in the part twos, like different forms? My class was divided between 2 different forms, and I was talking with my peers today when we went over the part two released online (form o) and we felt the other form (form f) was way harder and form o was more straightforward. Opinions?</p>
<p>And for further clarification, form o was the one that began with the spring that asked you for the velocity (the -sin graph). Form f began with the weight at the bottom of the pole that was part of the amusement park ride.</p>
<p>how feasible do you think this would be as a self-study (mechanics only) for next year? I took Physics B and will be taking Calc BC, and I was able to get a 27/34 on the 1998 released m/c (I know that’s not great considering it was a pretty mild test, but that’s without prep).</p>
<p>^ you should be fine</p>
<p>Could someone check my work on the 2012 Mech FRQ #3? And let me know if I’m doing it right. Part a and b i), I said that F = ma, so -(mu)<em>mg = m(dv/dt), solved for v and got v = v(0) -(mu)gt. For part a and b ii), I said that Torque = I(alpha), (mu)</em>mg<em>r = (mr^2)(dw/dt), solved for w and got w = (mu)gt/r. Then, for part c, I equated the equations for v and w, and solved v(0) - (mu)gt = r((mu)gt/r) to get t = v(0)/(2(mu)g). Then for part d, I substituted time in for the equation for v and got v = v(0) - (mu)g</em>v(0)/(2(mu)g) and after simplifying got that the velocity is v(0)/2. Finally for part e, I multiplied the velocity by time to get L = vt = v(0)/2 * v(0)/(2(mu)g) = v(0)^2 / (4(mu)g).</p>
<p>bumpppppp 10 char</p>
<p>I’m taking the make-up Physics C tests on Friday (May 25th). Any tips on last-minute studying for friday? I need to pull off a 4 on both tests to get college credit, so what’s the best way to study to get at least a 4 on mech and e&m?</p>
<p>I’m taking the late testing too. Btw I think your solution has some problems. In part (c) you are meant to set linear velocity equal to zero and find the time. Set that equal to L and then solve the quadratic equation to get the time. In part (d) you substitute the value like you said. Linear velocity is 0, find angular velocity. In part (e) we can’t apply x=vt because velocity changes with respect to time so we integrate v. Set distance equal to L and time what we got in part (c) to solve that. These are my solutions can someone please verify.</p>
<p>anyone want to have a tinychat about the late testing exam? I thought it was extremely easy by the way, at least compared to others ive seen</p>
<p>Yeah, I thought it was easy too. But because it was so easy I thought that I screwed up some of the FRQs. I took Mech and E&M by the way for late testing.</p>
<p>i messed up on mechanics mc aiosdjgoeijwafoi but other than that it was pretty good.
where’s the tiny chat link</p>