<p>To garfieldliker: Thanks for the quick reply. </p>
<p>Your friend is a math genius. If he has finished the entire undergraduate math curriculum, I would assume that he has already known most of the knowledge of Statistic. </p>
<p>My daughter has just finished advanced algebra, and she is a math OK student, not a math top notch student. But in her advanced algebra course, she has already learned some probability and statistic. She knows the concept of normal distribution, deviation, mean, etc. Not sure in her situation, know many hours need to be spent to grasp AP statistic.</p>
<p>garfieldliker: I mean Algebra taught in high school</p>
<p>This is the curriculum of the high school Advanced Algebra:
Linear Equations, Inequalities, Quadratic Equations and Functions , Logarithms and Exponential Functions , permutations, combinations, probability, statistic,etc</p>
<p>Next year they will learn Pre-Cal which include trigonometric</p>
<p>This looks to me like a standard Algebra 2 (Honors?) course in high school. That means she is ready to take AP Stats upon completion of this course.</p>
<p>Gratisfaction: Yes, she is ready to take AP Statistic course now, but she is considering self-learning it if it wont take too many hours. Not sure whether she can finish self-learning it in this summer.</p>
<p>This may sound bad, but the last 45 min of frq, I just traced over my pencil answers with pen. It was really easy. Multiple choice killed. I’m guessing the curve will be 68-75 as a 5, because of the easy frq, but this is just my guess…</p>
<p>Yeah, the FRQ seemed really easy…it took me like 30 min to do #1-5 then I epic failed #6c. Hopefully a 5…except MIT doesn’t take AP stats credit :/</p>
<p>I’m sure they graded sharply in such a way that those who couldn’t do the inference didn’t get 5s. After all, inference is the meat of any college intro statistics course. If you knew how to do that two-tailed t-test and whatnot, I’m sure you did fine.</p>
<p>Yesm, I am confident about the two tailed tests, etc. My teacher really sucked though, (he even admitted it haha) but I learned chisquared and slope regression lines in the hours before the test. but there were only 2 problems on chi and 1 on slope regression, right? and i knew them both.</p>
<p>So basically, you use the formula z = x-u/s. You do not have the center of the distribution, but you are trying to find how the 67th percentile relates to the mean if the standard deviation is .3. A z-score of .44 cuts of (bounds to the left) .67 of the normal distribution curve, so it represents the 67th percentile. Plugging into the formula, you get:</p>
<p>.44 = x-u/.3</p>
<p>Solving the equation, you get x-u = .132, so the value that represents the 67th percentile, x, must be .132 greater than the mean, u.</p>