Official December SAT Math Thread

<p>Did anyone get the one that was like, the median age of a group of 15 students was 17 and the oldest student was 20, and then it gave three choices
I. 3
II. 10 (?)
III. 14</p>

<p>or something like that? Was it all three?</p>

<p>and was the answer to the question with 60 cars and 83 people = to 49?</p>

<p>Jegan For that one It believe it was I,II, and III. For the 60 cars and 83 people i put 51. That one was a tough one... not sure</p>

<p>what about the question</p>

<p>a^2 - b^2 = 4....which of the following is a possible value for (a+b)?</p>

<p>I think I put -2</p>

<p>I omited # 17 in the grid-in questions..does anyone know the amswer?
There was also a question with a trianglw with sides 1 and 100; side c was opposite the 1 and side a was opp the 100..it was not a right triangle; what's the answer to that one?</p>

<p>yeah it was 51 cars and all I, II, and III</p>

<p>888888 can you explain how/why you put -2. goddd that one is raising concern for me...</p>

<p>jegan3, I got all 3 for that question with the median age.</p>

<p>Situtation I</p>

<p>3 people with the age of 17</p>

<p>X X X X X X 17 17 17 X X X X X 20 - just one possibility</p>

<p>Situtation II</p>

<p>10 people with the age of 17</p>

<p>17 17 17 17 17 17 17 17 17 17 X X X X 20 - again just one possibility out of many</p>

<p>Situtation III</p>

<p>14 people with the age of 17 - hahaha</p>

<p>17 17 17 17 17 17 17 17 17 17 17 17 17 17 20 - one possibility!!!</p>

<p>So it looks like all 3 was the correct answer.</p>

<p>And there was a question (15/16 i think) where the sum of all even integers from 2 to 202 is 10,302. what is the sum of 4 to 200. the answer is 10098</p>

<p>i put C hast the least angle because one side was a 100, one was 1, the other had to be 101>y>99, so therefor C would have the smallest angle because it faced side with length 1? what did you get</p>

<p>If the avg of a list X is x and of a list Z is z, and x<y<z, for a no. y</p>

<p>if the two lists are combined, which of the following can be the avg of the two lists combined</p>

<p>I. x
II. y
III z</p>

<p>i chose only II...</p>

<p>bt, I think the correct answer for that was something like 10,098 (A). If someone had a different way to do it and could show, please do because I was not sure 100% on it either. 2 to 202 INCLUSIVE was 10302 I believe. So, 4 to 200 INCLUSIVE would be 10302 - (3 + 201) = 10098. If my interpretation of INCLUSIVE (haha) is incorrect then I guess I am wrong, but it seemed like all the other answers were too large to make any sense.</p>

<p>ooo solsek you got lucky on that calculation. you woulda figured it out tho anyways im sure, but the sum was 10,302 from (2,202) inclusive. and it asked for (4,200) inclusive.</p>

<p>And remember it was just even integers in the set.</p>

<p>10,302 - 2 - 202 = 10098</p>

<p>2 and 202 would take out the lowest and highest in the set, because the next lowest and highest (since its just evens) would be (4,200)</p>

<p>what did you put for the year one..in what year will it be 3.5...i got 2017?</p>

<p>does anyone remember about that question with the triangle and the smaller triangle made by cutting off the top part of the larger one? and the base was 16 and the height was like... 10. and they gave you the height of the smaller triangle, which was like 4, and then we were supposed to find the base of the smaller one? i think i got like 6.4</p>

<p>hooha yeah thats correct, I believe they were just two similar triangles, and half the base was 3.2, therefore the whole thing was 6.4</p>

<p>grid in Question)</p>

<p>Centeral city: (number of people left) - / (number of people in) 12
Inter something terminal 1: (number of people left)3/(number of people in)10
Inter something terminal 2: (number of people left)5(number of people in)10
Air port:(number of people left) t / (number of people in) 12 </p>

<p>'c' represents the number of people who stay from central city to airport..</p>

<p>what is the greates value of c/t?</p>

<p>grid in Question)
-5≤ X ≤ 5
-5≤ Y ≤ 5
??? something like this.... and ...solve something </p>

<p>│X-Y│... this.... i can't remeber</p>

<p>ikir, for the bacteria problem, was D the correct answer?</p>

<p>ldu1207 </p>

<p>i got 12/10</p>

<p>which is 1.2</p>

<p>since 5-(-5) is 12/10</p>

<p>goldtx
i got D.</p>

<p>for the 1/(2x+1) < 0 or whatever</p>

<p>Was the answer the interval -7/8 < x < -3/8</p>

<p>because -4/8 would be the asymptote, and anything bigger would get you positive?</p>

<p>Someone confirm the bacteria problem. I got (1+r/100)^4 = 2.</p>

<p>Also, did anyone have the problem where it said line X intersected the y axis between (0,2) and (0,2.5) and had the equation 3x + 2y= k?</p>

<p>I put 4.5 for K, because for I just picked the point (0,2.25) and did 3x0 + 2x2.25 = 4.5.</p>

<p>I'm, not sure on the problem because I was rushing to finish one of the math sections.</p>

<p>ikir, for the bacteria problem, I think (1+r/100)^4 = 2 is correct. But do you remember if that's choice D?</p>