<p>first time for me to take the Math IIC, i was originally gonna take the IC. you guys forced me to make the right decision, i know i skipped 5, guessed on 3, 2 of them i got right. (according to posts on this thread)</p>
<p>problem #1 was 4/7
problem #2 was cube root of 10 or 10 point sumthing</p>
<p>there was a f(g(x))=1 or sumthing for values-that was g(x)=2</p>
<p>i got .8 for the probability 15/19- 19 possible sums-2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20
15 are greater than 5
how did u get .9?</p>
<p>anyone figure out that stupid arc length of chord i used the pidegree/360 * 2rpi but i cudnt find the stupid answer in the choices</p>
<p>one had to do with inverse of 2e i got like 3.74 or sukthin like that </p>
<p>maximum of sinxcosx-cant remember the answer cud just graph it tho</p>
<p>last question with absolute value-B-difference between x and -3 < 5</p>
<p>stem and plot graph-median i think it asked for i got 56 it was out of 9 numbers rite</p>
<p>anyone know if these questions are supposedly arranged in order of difficulty
it started easy til like 25 then stupid geometry problems and got easy after like 40</p>
<p>altoids - The sums one I did a 10X10 grid. There are 10 sums that are less than or equal to 5 (some are repeated) and the rest of the sums are greater than 5 (90 sums - some are repeated). (90 sums greater than 5)/100 total sums = .90</p>
<p>For the length of the chord problem:</p>
<p>Central angle 106 degrees and radius length 5. Draw the central angle and the chord. Split that isoceles triangle with vertex angle of 106 into two right triangles. The hypotenuse of each rt triangle is 5, the angle with point touching the circumference of the circle is 37 degrees [(180-106)/2], and the split 106 angle is 53. Cos(37) = (1/2<em>chord length)/5. 1/2 chord length = 5</em>cos(37) = 3.99 Chord length = 7.98</p>