<p>likeateusday:I got 28 for that</p>
<p>you have 25 negatives and 2,8, and 32</p>
<p>elliott: I also thought it was consecutive but then reread it and realized that it did not specify</p>
<p>If anyone else can verify that this was the question please.....</p>
<p>A sequence of numbers continues as follows 1,2,2,3,3,3,4,4,4,4,5,5,5,5,5, etc., What would the sum of all the previous terms be when the first 12 appears in the sequence?</p>
<p>Um guys, I got one. You can have any number of negative integers, then have one large positive one at the end to make it equal zero.</p>
<p>-It asked for position for 12 not the sum. Search the thread and you'll find out the answer is 67
^^elliot it asked for positive integers only ( ithink)</p>
<p>-@likeatuesday its 28</p>
<p>Oh yea for that one i think i put none</p>
<p>For the problem asking to find the value of "m" with:
(x-8)(x-k) = x^2 -5x + m
I got 24. What about everyone else?</p>
<p>its 16. You must expand left hand side and equate the variables.</p>
<p>Atomic is right it was 16.</p>
<p>Plug it in, considering that 8k=m</p>
<p>Really, i am pretty certain that the answer is 24?</p>
<p>Did you un-distribute to find that k=3 and then plug it in?</p>
<p>K=-2. The answer was 16.</p>
<p>Was this equation correct:
(x-8)(x-k) = x^2 -5x + m </p>
<p>Or was it actually this:
(x-7)(x-k) = x^2 -5x + m</p>
<p>(X - 8)(X - 3) does not equal X^2 - 15X + M</p>
<p>K should be two. The answer is 16.</p>
<p>I don't remember but I think I got 8 or 16. W/e this thread is making me nervous lol.</p>
<p>k =2
answer was 16</p>
<p>ok i'll do it out for you you bulbasaurian bastard</p>
<p>(x-8)(x-k)=x^2 - 5kx + m
if you factor the right you'll have (x-a)(x-b) where ab=m and a + b = 5k
then you realize that a and b are 8 and k
so you get 8 + k = 5k, k=2
8*2=16</p>
<p>who cares wat u think u remember getting, can someone just verify the asnwer, even if they have to do it over again?</p>
<p>what was the ribbon one
like u have 80 cm ribbon
if u cut out these triangles, what is the total lengths of the darkened ridges</p>
<p>i got 100
but then i realized i messed up and re did it and got like 96 i think</p>
<hr>
<p>it could have been 0+0+0...no?
i put one as well, but i guess that's wrong, the answer should be none
dammit</p>
<p>it's 100 tencharacters</p>
<p>proscastinate, that's clever but i think they maybe said different integers</p>
<p>guys..i am pretty sure it was 130..
i read the problem 6 times..i don't see how it can be 90..=.=</p>