<p>there are four letters in a bag</p>
<p>A,B,C,D...</p>
<p>What is the probability of getting in the order of A,B,C,D..</p>
<p>1/4 * 1/3 * 1/2 * 1= 1/24?? is that right?</p>
<p>you got it.</p>
<p>What is the experimental for math?</p>
<p>I had a rectangle vertex problem</p>
<p>the rs=something then r^2st....</p>
<p>um..grid in with like slope of line between .5 and .55</p>
<p>didn't have a vertex problem..</p>
<p>what did you guys get for one about equilateral triangle?
it asked for the line that had four times as much length as AC or something..</p>
<p>was it just the whole side of the biggest equilateral triangle?</p>
<p>there are four letters in a bag</p>
<p>A,B,C,D...</p>
<p>What is the probability of getting in the order of A,B,C,D..</p>
<p>1/4 * 1/3 * 1/2 * 1= 1/24?? is that right?</p>
<p>i thought it was how many ways are there to arrange the letters?</p>
<p>no it was like this..</p>
<p>N,P,W,R...</p>
<p>it asked for</p>
<p>R,P,W,N or to that extent..in other words it was in different combo then the first one...so i remember clearly..sorry bro..</p>
<p>does it make a difference that its in a different order isnt it still 1 out of 24 because R P W N only appears 1nce</p>
<p>its simple guys, 4!</p>
<p>how is that 1/4?</p>
<p>alright. did anyone manage to get the answer to this one?</p>
<p>(a^3)^x = 9^y</p>
<p>if i remember correctly, all three variables were positive integers, and we were supposed to find the maximum value for x.</p>
<p>you mean minimum value for a...i think it was 3?</p>
<p>there are four letters in a bag</p>
<p>A,B,C,D...</p>
<p>What is the probability of getting in the order of A,B,C,D..</p>
<p>1/4 * 1/3 * 1/2 * 1= 1/24?? is that right?</p>
<p>i thought it was how many ways are there to arrange the letters?</p>
<p>so who's right??</p>
<p>is 1/24 correct?!?</p>
<p>did anyone get the cheese question?</p>
<p>it was a huge cylinder 2 inches high (of cheese). A piece was cut out at a 30 degree angle. That piece weighed half a pound. So what is the total weight of the chunk of cheese.</p>
<p>--My response was:</p>
<p>(30/360) x 0.5 (PS: This was number four)</p>
<p>but I can't help but think I answered it wrong, I didn'teven use one of the givens (2 inches high) and I know it wasn't there for nothing.
Help please.</p>
<p>For that one I just did 360/30 = 12
Then multiply 12 times 0.5. It was asking for the weight of the whole block uncut right?
so yeah, 12*0.5 = 6</p>
<p>for the f(x) find k problem. did the problem say that it couldn't equal 0? i put 0 and now i feel really dumb. i hate making these stupid mistakes.</p>
<p>oh, and what number did you get for x on the number line problem....0, 1/x, 2/x, 5?</p>
<p>I believe X was 3/5.</p>
<p>ditto. 3/5.</p>
<p>ive taken teh sat twice before... got 730/720 on the math and this time i think i did a lot worse on the math... there wer ea bunch of tricky problems... maybe its cuz im in stats so im not taking a rel math class, but still, i thought it was way harder than other math sections ive taken</p>
<p>(a^3)^x = 9^y</p>
<p>the question was asking for the minimum value of a if a, x, and y are integers.</p>
<p>i put a =1....because couldn't both x and y be zero?
(1^3)^0 = 9^0</p>
<p>Oh damn. You're right. I put 3 for that one. Damn. So far that's 2 wrong. Not looking so hot after I originally thought I aced it. And both I got wrong because I forgot to count 0. LOL OWNED.</p>