<p>can an math experimental section be a grid-in? Apparently, I don't recall any of the grid-in answer compilations. Anybody feel the same?</p>
<p>mun: Yes. It can be. Or it could just be another version of the 4 November, 2006 SAT examination.</p>
<p>J-sus: Yes, an 800 is generally not possible after any raw points are lost. As someone said earlier (missing or omitting one with all the rest correct) will probably yield around the 780 range (October/November tests).</p>
<p>Did anyone have Grid-in Section 4??</p>
<p>Yeah I had that.</p>
<p>I believe I did. Remember any particular questions?</p>
<p>woah i had a wayyy different test from you guys, but again im an international.</p>
<p>ETA- did someone have math for sections 2, 3 (and both didnt have grid ins)</p>
<p>What is the score for 4 wrong on the math section?</p>
<p>like a 710.</p>
<p>i didnt get to answer the last one it was like: R^2XY=400 or 200 or 300 and RX=40 or something. i put something like 10</p>
<p>Was there an answer? r square root of 2pi</p>
<p>No. Grid-In</p>
<p>how abou 10 wrong?</p>
<p>I didnt even get to look at that problem for more than 10 seconds. i put a random answer bcz it was a grid-in</p>
<p>according to [url="<a href="http://talk.collegeconfidential.com/showthread.php?t=219270&highlight=math+curve%22%5Dthis%5B/url">http://talk.collegeconfidential.com/showthread.php?t=219270&highlight=math+curve"]this[/url</a>], that would be about a 640.</p>
<p>did anyone have the question with a rectangular prism, and they made a right triangle in it and it asked what the area of the triangle was?</p>
<p>did anyone have a logics question involving three kids going to see the movies lol.</p>
<p>yeah i had 13 too.. i was nervous because i did this quickly. it was somewhat a confusing problem.. not sure why</p>
<p>nope, sry. i got one that asked what the diagonal of the rectangular prism was. i got 13 for that. i kept putting it in my calc over and over again and it gave me this weird answer and finally when i came back, it worked. lol, iono how that happened.</p>
<p>im still confused to what the poster question asked</p>
<p>ok Nicole07. The question was like this (not sure about actual $ amount): $48 were made in one day selling posters. the deal is 6 for 5$ or 1 for 1$. What is the least amount of posters that could be sold?
1. 48/5 = 9 w/ a remainder of 3
2. 6<em>9=54= number of poster sold with deal
3. Add the remainder from part 1. 54+3=57
</em>*This is assuming the amount made was $48. the method is the same always</p>