<p>(4-1.75)^2pi</p>
<p>For the concentric circle you had a circle with a radius of 4, and a circle inside of the with a radius that was like .75 less than 4. So for the area of the inner circle you have like (4-.75)^2*pi</p>
<p>oh yeah ^ 1.75 sounds right</p>
<p>someone said some perimeter question was “64”??</p>
<p>21.99 on gassssssssssssssssssssssssssssss</p>
<p>List of the ones I got wrong
120 I put 25
88 I said 84
26^5(10) I’n not sure whether I got this one right or not
ht=16t^2 +32-48… I put 16. I think I was high</p>
<p>My batteries actually died on question#10. I had a panic attack. After blanking out on everything for 5 mins, I got myself back together an kept working. Half way in, my calc came back. Those 5 mins were costly, cuz I had to rush to through everything else. Probs made some other carless errors too. ■■■
I’ll cry if I get lower than a 28 on this section
31 on english
36 on reading
33 on science
comp =32
probs 12 on essay</p>
<p>My proctor was a tool and refused to lend me a calc when mine died :(</p>
<p>^What was the answer to the ht=16t^2 +32-48?</p>
<p>r u sure it was 2(4-1.75)^2pi or someting</p>
<p>^ I think it was just (4-1.75)^2pi</p>
<p>"someone said some perimeter question was “64”?? "
Yeah that was a parallelogram question. they gave you one side, you had to find the other three.
I think it was 10, 10, 22, 22</p>
<p>"^What was the answer to the ht=16t^2 +32-48? "
people are saying 1 or -2. I wish I knew the exact problem. I would solve it for you.</p>
<p>was definitely (4-1.75)^2pie or
4(outer circle radius)-1.75(distance) gives the inner circle radius and area formula is (pie)r^2</p>
<p>^That’s what I got- it asked you to find the other three sides</p>
<p>@vince011, the answer was 1 second. and you are correct about the concentric circles one.</p>
<p>I love how we all go on CC right after the ACT :D</p>
<p>What’d you guys get for the area of the rhombus? I didn’t know how to do that one, so I found the sides and multiplied them togther (5 x 5 =25).</p>
<p>^I couldn’t remember the formula from geometry…but I thought it was 1/2 (6) (8) so I put 24</p>
<p>area of the rhombus was 24.
3(4)= 12…there were 4 of these triangles…so…
12(2)= 24</p>
<p>area of rhombus is diagonal1*diagonal2/2</p>
<p>but i wasnt sure so i just split it into 4 triangles and did it that way</p>
<p>what was the height of the tent thing… like to the closest foot = 5</p>
<p>ya because it was base of 3 (6/2) and height of 6 so pythagorean
6^2-3^2=(sq27) which is around 5.14 or 5</p>
<p>what was the answer iwth the volume of a cylinder and like…if the height was incrased by 2 and teh base increased by 3…or somethng like that. Was it …the new shape would be 12x as large?</p>