I’d recommend going through the practise tests first, if you have a good foundation of chemistry
This seems like a good review I happen to find:
http://www.csh.k12.ny.us/webpages/rcolascione/files/review%20packet.pdf
Would it be worth spending time on Kpa/Kpb/Buffer PH calculations?
Annnnnd I’ll ask again…
Do we have to do the collegeboard test online?? Cuz I can’t find a pdf to print out!!
Could someone pleaaaase send me?
Can someone open the Barrons book to the 4th practice test in the back and take a look at # 60 and then explain it to me because I kind of don’t understand it?
@YoohooAddict This question takes into account heating curves. To melt 5 grams of ice at 0 C, you would multiply the heat of fusion by the number of grams of ice you are melting. (334 J/g * 5 g = 1670 J) Therefore, 1670 J of energy are used to melt the ice.
For the second part, first calculate how much heat you would need to heat the water to 100 C before it starts to boil. Using q = mcT, q = (1 g * 4.18 J/gC * (100-4)) = 401.28 J. Since there is still plenty of energy to be used (started with 1670 J), calculate how much energy it would take to vaporize all of the water using the heat of vaporization provided by the question. It would take 2260 J of energy to evaporate all 1 g of the water. As you can see then, it takes a total of 2260 + 401.28 J of energy to heat and vaporize 1 g of water at 4 C completely, but since you only have 1670 J, you can only heat the water up to 100 C and evaporate most, but not all, of it, so the answer is D.
I hope that makes sense!
What colors do we need to know?? Just flame tests right?
I think also compounds of sulfide with metals.
Can someone explain electroplating to me?
@dminzi I don’t think electrochemistry will come up on the test, but basically, you have a metal and an object to be coated in aqueous solution; you make sure that the anode is the metal and the cathode is the object. At the anode, oxidation occurs, and metal atoms are transformed into metal ions, dissolving in the solution. These ions are drawn to the negatively charged cathode, where electrons are flowing in courtesy of the power source. The ions are then reduced and coat the cathode.
@dminzi Oh yea that’s simple. Basically it’s the same as reduction in a redox reaction.
So I figured this out yesterday after the test, so I actually got it wrong.
So let’s say AgNO3 ionized and formed Ag and NO3
What is the mass of Ag when there are 4 moles of e- (electrons)?
Well to go from AgNO3, Ag lost it’s pluz charge which means it gained an electron. So another way to write this would be:
Ag+ + 1e- --> Ag
so mole ratio: 1 mole Ag/ 1 mole e-
4 e- x (1mole Ag)/(1mole e-) = 4 mole Ag then conversion factor: (108 g/ 1 mole Ag), so multiply: 4 mol Ag x (108 g/1 mole Ag) = 432 grams of Ag.
Scored 75 on the first Barron pratice test, not sure how you guys did, but is that pretty bad? okay? good?
you mean 750? I’m doing about the same, but I make so many careless mistakes T_T
I’m bout to go to sleep now to rest my head. However, can someone answer these questions for me:
How many T/F questions are there really on the test? (like the CB one).
Which compound of Nitrogen and oxygen has a color?
Explain what Dumas experiment is.
What should I bring with me tomorrow to the school site?
ink is separated by chromatography right?
good luck tomorrow guys! If any of you are up studying (like me) i highly recommend Khan Academy on youtube.
lol i’m trying to get a good night sleep.
and if any of you are up, do you think we need to memorize things like the amount of energy to boil water and specific heat?
I can’t sleep…I still have 3 practice tests to go…
I’m just praying that I’ll have a 750+ score. Yall trying too hard lol.