<p>The area of the region enclosed by the graph of the polar curve r=1/((sin(x)+cosx)) and the x and y axes is?</p>
<p>I first thought the enclosed area should be one quarter of the circle since i get circle for the above equation.
Help me why does the answer say it is isoceles triangle !!!</p>
<p>Because this equation actually represnts a line not a circle.</p>
<p>Yeah, I get this: <a href="http://i41.tinypic.com/21buhx0.png%5B/url%5D">http://i41.tinypic.com/21buhx0.png</a>.</p>
<p>Can anyone tell me how the function should be typed in the calculator
Thanks</p>
<p>r(cosx+sinx)=1
rcosx+rsinx=1
x+y=1 by definition
y=1-x</p>
<p>This has intercepts at (0,1) and (1,0) when graphed on the x-y plane. Is the answer .5?</p>
<p>I second .5 as the answer. If you don't know how to do it, just graph it. Make sure it's in radian mode, and polar mode. For the window, just make sure that theta is big enough so that the isosceles triangle is made.</p>
<p>Yes. And you could always integrate it using your calculator, but that's harder than anything else.</p>
<p>I think solving it is the easiest way, if you know basic parametric/polar properties (like x=rcost and y=rsint, that's about it for this problem).</p>
