<p>I first heard this on the news, but I'm sure there have been quite a few articles out by now. I think the 3 year degree is feasible, but only for certain majors (humanities) but not something like engineering. More OOS, seems like a possible, but the main goal of the UC is to educate the people of Cali., so it would suck if you were replaced by some rich kid from another state. The last solution--I would laugh at that, b/c then you're really "buying" the degree, if it came true, I'd be glad I wasn't attending LA or Cal.</p>
<p>Anyway, these are just some of my thoughts, I wanna hear yours. Discuss!</p>
<p>I thought about graduating in three years, but I’m not sure if it’s worth it. I think the extra year will help one get more experience and give more time to search for job opportunities. The job market can only get better after each year at this point.</p>
<p>A three-year degree is totally feasible in engineering, especially if one takes summer classes. Engineering degrees require 120 units - most of the people I know (how many engineers didn’t score a 5 on Calc BC?) came in with 25~35 AP/CC units, and take an average of 28~36 units per year (not counting summer sessions). Toss in a summer session or two if necessary and it’s not hard to get out in three years, especially for a degree like EECS where the pre-req chains are short and the UD requirements are very flexible. People choose to stay for four years to take more classes, double major, do research, whatever.</p>
<p>As long as they don’t increase OOS costs any more than they’ve already done. It’s costing me 52,052 per year to go to UCLA if I decide to. They need to find the equilibrium at which the maximum number of applicants will attend. Raise the costs to 55,000 and you get diminishing returns out the rear, even more than are already occurring.</p>
<p>If I heard correctly, their other option would be to implement annual 5-15% tuition fee hikes over a period of 5 years. (May be a hearing error on my part but it sounded like that was a possible option)</p>