<p>Page 374, Number 25</p>
<p>kind of surprised and annoyed that no one has posted this problem on the consolidated list.
Anyways, asks you to find Z but there are 2 variables (X and Z). Cannot set up system of equations without dragging in a third variable.</p>
<p>How do you solve?
system of 3 equations? ( i kind of didnt even try this because i got lazy plus ran out of time)</p>
<p>please help!!!!!</p>
<p>thanks.</p>
<p>Don’t have the book, but maybe vectors, judging by what you’ve said the question talks about.</p>
<p>It’s quite simple to do simultaneous equations with 3 equations. Have you already tried this?</p>
<p>redraw the triangle so it’s easier to see that it’s isoceles. <C = z. Then:</p>
<p>y = 180 - 2z</p>
<p>x = 180 - z - (z/2) ; this is because CD bisects <C, so the angle for the lower triangle is z/2.</p>
<p>x = 180 - 3z/2</p>
<p>x/3 = 180 - 2z</p>
<p>(180 -3z/2)/3 = 180 - 2z</p>
<p>60 - z/2 = 180 - 2z</p>
<p>3z/2 = 120</p>
<p>z = 80</p>