Constant function is still a function?
@luckykansasmath Wasn’t the probability one very logical? The two success rates were really high, so the chance that at least one succeeds should be higher than both and there was only one answer that was higher wasn’t it like .98 or something
@luckykansasmath I think @Newdle is drawing a distinction between “function” and “function of x.” Question asked for function of x.
@luckykansasmath it was .9968, (.997) because of complimentary counting
for the probability one, I just found the probability of both alarms NOT being successful, and then subtracted that from 100%
Did you guys get something like 108*pi for the 6 inches above plane one?
@Newdle i put 36pi. The set of points less than 12 inches from the point and contained on the plane would be a circle with radius 6 (i think), so pir^2 = 36pi
yeah 108pi is what I got too
Guys, getting a 780 and getting a 800 will make how much difference? Technically an 800 is like a 80%. Will the ivies care THAT much?
Two questions. I would appreciate a response w/ explanation if possible.
The cards question. Was it 35? For the probability to be 1/2? or was it 34
The combination of numbers 1234… how many were there and explain please?
@therealdeal23 that answer for the roots one was E correct?
Cards: I put 35, because there are 24 cards between 10 and 35
Combinations: Possible combinations (3 must come immediately after 2):
-1(23)4
-4(23)1
-14(23)
-41(23)
-(23)14
-(23)41
=6
6 combinations - 1234, 4231. 2314, 2341, 1423, 4123
@ahmdp90 I said 34, but people are saying 35. If you drew a 10 then there are 49 cards left. Draw a 34 and there are 48 cards left. 34-10 = 24 / 48 cards left = 1/2.
Combination one there were four digits _ _ _ _ and two of them had to be in a certain order ab and then there was 2 options for the other spots, of which there was three. a b _ _ and _ ab _ and _ _ ab so the answer was 6
I think it was 35? because there had to be 24 numbers available in the middle and you need to include 34 for there to be 24 numbers so the second number was “35” because the numbers were in the middle.
combination i believe was 3X2X1= 6 because “three has to go after two”, so technically that’s one choice so for the first spot you can have 3 choices, then 2 choices, then one choice.
do you guys remember the answer for the one with all sorts of variables and we had to (plug in? and) simply them? it included like h^2x^2, 10x, 5h, etc…
i got e for that…
@hsgirl1226 something like 10h+x ?
@ahmdp90 it is 35, because you have to take out 35 and 10, and since there are 26 numbers between 10 and 35, you’re left with 24 numbers overall that you can choose.
10hx - 5h^2 - 5? not too sure abt those negatives
@jahnbrown i chose the longest equation…which was e… i guess i made a calculation error… 