Sat Chem Problem. Please Help!!

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1

Calculate the molarity of barium hydroxide if
34.30 ml of Ba(OH)2 will be needed to neutralize 76 ml of stomach acid if stomach acid is 0.14 M HCl?
Ba(OH)2 + 2HCl =>> BaCl2 + 2H2O

2

If you have 76 ml of a 0.14 M HCl solution then you have .076*0.14 = 0.001064 moles of HCl.

To balance the equation, you will need 5.32*10^(-4) moles of Ba(OH)2.

Then divide 5.32*10^(-4) moles by 0.03430 L to find the molarity.

3

@MITer94 Thanks!