SAT June 2013 Questions Review

<p>Share questions that were confusing and someone answer these for us please.</p>

<p>I will post questions I remember. Thank you.</p>

<p>Math Question</p>

<p>Can anyone answer math question that was in the short section???</p>

<p>The information given was that there was 2 quadratic function, one was concave up and the other was concave down, and they had same two x-intercepts.
The question was to ask how many are there other quadratic functions having same x-intercepts that can be graphed rather than two functions already shown???</p>

<p>(a) None
(b) 1
(c) 2
(d) 3
(e) More than 3</p>

<p>Also, another math question</p>

<p>There was like n = 100110021003…1020
n is like continuous numbers from 1001 to 1020. If you add the digits what is the total number added all together???</p>

<p>These have already been answered in another thread. But the quadratic one was more than three, and the math question was 122.</p>

<p>Agreed with spazzer4501 with both answers</p>

<p>why is it 122?</p>

<p>A better question to ask is why is it not 122? Explain your thought process.</p>

<p>Here is how I solved the 1001-1020 problem if it helps…</p>

<p>Notice that from 1001 to 1009 the digits are a series (discrete math! yay!) form 2, 3, 4,… 10 and 1010 to 1019 is a series from 2, 3, 4,…11, and then 1020 is just 3. You can get the answer somewhat easily by taking sum of 2-10 or n((a1+an)/2) + sum of 2-11 or again n((a1+an)/2) plus the extra 3 (which is the tricky part). For the first series an=10, n=9, a1=2, the second series you just add 1 to an and n because there is one extra term. So the answer to the question is 9((2+10)/2) + 10((2+11)/2) + 3 = 54 + 65 + 3 = 122. This is much easier than going 1+1+1+2+1+3+1+4 (see the pattern?). Very tough problem but not insurmountable.</p>