SAT Math problems, please help?

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<p>From the latest edition of the BB, Practice test #4 sections 3 and 6</p>

<p>I was wondering if anyone on here could help me work out any of these math problems? They're mostly the ones I got wrong, and I'd like to know how to solve them. Much appreciated, thanks in advance!</p>

<p>6.17…</p>

<p>10 chime 8 (n) times @ 8 (n) :00. 10 x 8 = 80 total chimes
5 chime 8 times @ 8:00. 5 x 8 = 40
3 chime 1 time @ 8:00. 3
10 chime 1 time @ 7:30. 10
3 chime 1 time @ 7:30. 3
10 chime 1 time @ 8:30. 10
3 chime 1 time @ 8:30. 3</p>

<p>Add up the total chimes = 149.</p>

<p>6.18…</p>

<p>4 (4 options out of 5 cards because shaded can’t be 1st) x 3 (3 options for the last spot, because shaded can’t be last, and neither can the square that you picked for spot number 1) x 3 (3 options left because shaded square CAN be here… first two picked cards cannot) x 2 (two cards left) x 1 (only one option left) = 72</p>

<p>6.8…</p>

<p>All of a trapezoid’s inside corner angles add up to 360 degrees. So, look at them: top left corner = b, top right = a + c, bottom right = b + b, bottom left = a. So, subtract all of the a’s & b’s to find c.</p>

<p>360 - 2a - 3b = c</p>

<p>3.15…</p>

<p>Prime means that it can only be divided by itself and 1. 38 breaks down into 2 x 19. 100 breaks down into 50 x 2, the 50 breaks down into 25 x 2, and the 25 breaks down into 5 x 5. 5 is prime. 19 + 5 = 24.</p>

<p>3.18…</p>

<p>Couple ways of going about this: plug in numbers, or use straight variables. I’m going to plug in because, imo, it’s easier to understand.</p>

<p>Say x = $5.00. z = $2.00. 10 (n) total shirts.</p>

<p>Your first shirt is $5.00. Your <em>remaining</em> 9 shirts are 9 shirts($5.00-$2.00) = $27.00. Equals $32.00.</p>

<p>In other words… x + (n-1)(x-z) = n.</p>