<p>-3 <(or equal to) n <(or equal to) 8, then what is the range of possible values of n squared.? </p>
<p>the book says 0 <(or equal to) n^2 <(or equal to) 64</p>
<p>Can you explain why it is Zero?</p>
<p>And if I was adding ranges that have opposite inequalities pointing in different directions (if 2<x<11 and="" 6="">y> -4, what is the range of possible values of X+Y?) How do i know which inequality symbol to put for the answer?</x<11></p>
<p>To your first question, I think it should be 9 instead of 0. Maybe the book is wrong; which book are you using?</p>
<p>And for the second question, If you look at it like this:
6>y also means y<6; and y>-4 also means -4<y. So when you put these together, you get -4<y<6. Now you can add them to get -2<x+y<17.</p>
<p>i got the question from the SAT math I and II Princeton Review. They have 0 as part of the answer, and I thought it was 9 as well</p>
<p>Princeton Review tends to have some mistakes here and there</p>
<p>Zero is in the domain, which is [-3,8].</p>
<p>Of all the numbers in that domain, it’s 0, not either of the endpoints, that has the smallest square. While it’s true that (-3)^2 = 9, and 8^2 = 64, you’re overlooking the fact that 0^2 = 0.</p>
<p>If this isn’t obvious, graph y = x^2, and examine the graph in the range -3 < x < 8. The parabola has its minimum at (0,0), so 0 is the minimum value of the range.</p>
<p>^And that is why I only get 710s on my practice tests T_T </p>
<p>Good job though Sikorsky!</p>
<p>okay 
thanks SCHOOLISFUN and SIKORSKY!!! Appreciate the explanations haha!</p>
<p>School, don’t take it too hard. If it helps, I’m a math teacher, not a math student.</p>
<p>Imagine, yw.</p>
<p>Oh! haha I’m still only a sophomore so it’s okay for now :D</p>