SAT Question of the Day

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<p>The</a> Official SAT Question of the Day</p>

<p>Anyone wants to explain how they approached it?</p>

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<p>The “t” stands for the x coordinate. And since it says that “v” is the y coordinate, it’s basically asking what the range is from 0 to 5 on the x axis. And as you can see, from 0 to 5, the lowest value is 5 and the highest value is 10. Thus the answer is [5,10] or D</p>

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<p>I don’t understand your explanation. It basically asked for the range of v, but I don’t get why it’s 5 -> 10.</p>

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<p>because if you plug in 0 for “t” you get a value of 5 for v (the point (0,5)). Plug in values for 1-5 for “t” you will see that out of all the values you get for v, everyone of them is in between 5-10. Thats how you get the answer!</p>

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<p>ok look generally we put (x,y) right? X is the horizantal distance, from left to right. Y is the virtical distance, up and down. </p>

<p>Now look it tells you that t is greater than or equal to 0 and also that t is less than or equal to five. From that we can say that the place we are looking at is anyone of the points from where x=0 to x=5. That includes where x=.35, x=3.14, etc.</p>

<p>Now it is asking us for the ‘v’ value. now the ‘v’ value is the y values from the inequality t is greater than or equal to 0 and t is less then or equal to five. so basically so you could visualize this. draw a point (0,0) on the graph and (5,0). Connect the points and make a line. Now draw point (0,10) and (5,10). connect those points to form a line. you know have two lines. now connect those two lines to form a quadrilaterall.</p>

<p>Now that quadlirateral is the section you must look at. To find the possible ‘v’ values you simply have to find the lowest value of y inside or on that quadrilateral (5) and the largest y value (10). So in that area which we have isolated we can say that v has to be greater that or equal to five and that v is less than or equal to ten.</p>

<p>Basically you need to find the range of a part of a function.</p>

<p>I hope I didnt make it more confusing, I was just trying to explain it in a diff. way.</p>