<p>Get a discussion going on.
My question is 151 B....Is the H30 and heat just a deprotection? But I can't seem to get it right</p>
<p>i couldn’t answer a single freakin problem on the problem set…</p>
<p>ugh yeah it’s hard… i’m getting really confused on all of the 9th one</p>
<p>Yeah 151b is just reverse protection.</p>
<p>how is this year’s nomenclature going to be different? i didn’t understand the point he was trying to make in class about that.</p>
<p>i can’t synthesize anythinggg =/</p>
<p>you just gotta how to do the sugars and he’ll provide you with the base name…something like that. i don’t think it’s gonna be too different.
here’s a general question…how can you tell when something is gonna have stereoisomers? (298 a for example…)
I’m only on problem set 1. Fantastic hangover yesterday. lmao Such a bad idea to party friday.</p>
<p>it can either attack from top or bottom, so that’s 2 possible orientation around that carbon</p>
<p>then there’s another stereocenter on the left, so that’s another 2 possibilities</p>
<p>so total possibilities = 2*2 = 4</p>
<p>Question about treating maltose with NaBH4/MeOH…</p>
<p>Pedersen says nothing can happen at the acetal, but why can’t MeOH be a source of protons? Is it because the hydride ions from NaBH4 will take them too quickly before the glycosidic -O- can take them?</p>
<p>is a hydrazone an imine?</p>
<p>about your second question, i’d like to say no. but i mean it could be that the R group is just NH2</p>
<p>where did s/r -carvone come from? I’m guessing that they were the MOD right after the first midterm…cuz I didn’t go to that one. :(</p>
<p>what he said about them?</p>
<p>we don’t even need to know facts about them, they’re just going to show up as problems like on the last midterm</p>
<p>yeah, but he gave mechanisms w/ some of the others, i guess he didn’t w/ this one?</p>
<p>why are there so many random reagents in the problem sets…
did we ever learn BH3/HOOH on page 335?</p>
<p>it’s from chem 3a, making alcohols from alkenes</p>
<p>i bet almost everyone got that one wrong that year lol</p>
<p>good god i’m set sail to fail. literally. don’t remember anything from the first half of the semester and all these reagents keep popping up…</p>
<p>anyone know what’s going on in 11d? how does it go to the final conjugated product?</p>
<p>you’re probably just allowed to mess around with the H3O+/H2O as much as you want… there’s no other way to get it to be conjugated</p>
<p>would you guys get the syntheses on 83a/84?? because i can barely understand them after looking at the answers</p>
<p>Yeah its a beta-gamma reaction that he didn’t teach in lecture. You just do the normal cuprate addition and reform the carbonyl. Then like futterfly said you take an alpha hydrogen from the other side making a second enolate and than when you reform the carbonyl it makes a alpha-beta unsaturated and the beta-gamma unsaturated is kicked off and takes a hydrogen proton. Molecules always prefer to be conjugated so whenever you see a beta-gamma it’s usually best to convert it to alpha-beta.</p>