<p>It was 0 and 2 because if you graphed it, they intersect at 2 and 0 is obvious.</p>
<p>What would a -4 to -7 be?</p>
<p>You guys, the trapezoid one was E. They didn’t even give both bases…there was insufficient info.</p>
<p>4 probably 31 or 32 and 7 probably 29 or 30</p>
<p>it wasn’t insufficient info for sure 100%</p>
<p>Oh I know why i put only 2:</p>
<p>2t = t^2
2 = (t^2)/t
2 = t</p>
<p>Math fail?</p>
<p>JDE, there was sufficient information. You had to draw an altitude and from there use pythagorean theorem to figure out bottom base. From there it was just the trap. formula</p>
<p>What was the awnser to that trapazoid one? I forget that question but I got an awnser</p>
<p>Im pretty sure ive never ever used that on the act math test in like 4 tests lol but im pretty sure I got it right I just can’t think of tge problem</p>
<p>■■■, I should have seen that.</p>
<p>Edit: Wait, where do I draw the hypotenuse?</p>
<p>JDE, Yup 25 is right. </p>
<p>but for negative thing: i put the cubed on top one x^3/ something</p>
<p>trap. one : average of bases X the height. 24.
pyth. theorem for the other base, it came out to one base 10, other 6</p>
<p>yeah…one leg of the triangle was 4…the missing side was 3 which was also the witdh I guess of the trap. And they gave you the lenght of one trap base which was 6. So the triangles area was 6 and the rectangle was 18 so 24 all together</p>
<p>@Galib, missing side length was 4, but the way you solved it nullifies that problem</p>
<p>Oh lol my bad haha</p>
<p>How do you solve the (2,230 deg.) one?? when do they teach it?</p>
<p>ugh, I don’t think I did very well on the math section… but I think I did really well on English and Reading, so hopefully it will balance out</p>
<p>^^ Well, it’s a vector. All you need to do is realize where a 230 degree angle would be in relation to all 4 quadrants. It’s quad 3.</p>
<p>There’s no x=2 in quad 3?</p>
<p>Thats what caught me up also web… UHHHH I had 3 but then secretly changed it to 2 during the writing section… uhhhhh</p>