Solving Quadratic Equation Using Box Factoring

<p>f(x)=6x^2+9x-6</p>

<p>Where does this function intersect the x-axis (i.e. what are the roots or zeroes of f(x))?</p>

<p>Solve by factoring using the Box Method. When I use the method that is shown on this website Factoring</a> Quadratics: The Hard Case for this particular problem I end up with this as my factored down version of the equation.
(6x-3)(3x+6)
But that is wrong because I would end up with 18x^2 instead of 6x^2.</p>

<p>My question is that does using the method on that website to factor down a quadratic work for this equation? If so, could someone tell me what I'm doing wrong.</p>

<p>Thanks</p>

<p>Hahahahahahahahaha. Is this a serious question…? I really don’t want to be punk’d here.</p>

<p>Anyhow, graph on calculator. :D</p>

<p>Did you try taking out a factor of three first? Makes things easier. Looks like you have an extra factor of three in your answer…</p>

<p>so factor out the greatest common factor which is 3. so you get
3(2x^3 +3x - 2). then you factor the inside of the parentheses.The factors of -4 that add up to 3 are 4 and -1. so you get 3(2x-1)(x+2).</p>