some help on math question (march 2005 test)

<p><a href="http://i19.tinypic.com/6jz1275.jpg%5B/url%5D"&gt;http://i19.tinypic.com/6jz1275.jpg&lt;/a&gt;&lt;/p>

<p>Note: Figure not drawn to scale</p>

<p>In the figure above, AC = 6 and BC = 3. Point P (not shown) lies on line segment AB between A and B such that line CP is perpendicular to line AB. Which of the following could be the length of line CP?</p>

<p>The answer is 2.</p>

<p>I've been stumped on this for a while and still can't figure it out.</p>

<p>Help is appreciated. Thanks.</p>

<p>Well the answer can be a lot of things... I am assuming it was a multiple choice question because it says which of the following. If you give the other choices, I can definitely help you. I have it figured out, but it can also be something like radical 5... If you have the other choices, I would be glad to help you out.</p>

<p>key word in the problem is could be. when you draw the segment CP, which is perpendicular to AB, you have created a right triangle with a hypotenuse of length 3 (which is segment BC). therefore, CP must be less than 3. that's the best i can do for now cuz i don't know the other answer choices</p>

<p>if there are two or more choices less than 3, please post them</p>

<p>The answer choices are:</p>

<p>A - 2
B - 4
C - 5
D - 7
E - 8</p>

<p>yes then, if those are the choices than as stated previously, the hypotenous must be the largest side in a triangle</p>

<p>yeah there are many ways to look at this problem. D-Yu's solution would be the quickest. What I have noticed about hard problems on the SAT is that the answers are very different. In other words, you do not have to be that precise in doing the work; that is why D-Yu's solution is the best, and I don't want to clutter it up with all my thoughts.</p>

<p>dude, I don't see what other ways there are to solve it, since you're not given angles or anything, isn't just knowing the length of the hypotenouse > other legs the only way to solve the problem? or am I missing something?</p>