<p>I would disagree with some of your answers @benevolent for them.</p>
<p>Could you explain how the acceleration is not Fcost(theta) / m?</p>
<p>You may be right about the speed of light thing…</p>
<p>Theta on the electroscope increases only; I am positive.</p>
<p>Was the quasar thing correct? I guess that too. And I agree what a ******** question.</p>
<p>@injectmagic
Stars collapse into black holes somewhere in the process.</p>
<p>The triangle spring graph was potential energy since (1/2)kx^2 is PE of spring and the graph was F/x, so area was (1/2)F(X<em>2-X</em>1). Substituting kx for F of s, you straight up get the PE equation of (1/2)kx(DeltaX)= (1/2)kx^2.</p>
<p>What did you all put for the rotating wheel and the brick,Is it normal force?</p>
<p>Wasnt the induced current question I, II, and III?</p>
<p>hey guys.I took it today for the first time and I think that it is hard.It doesn’t like PR’s style. I am gonna take again. Also I remember that there is a question about thermal physics which includes a chart. Can anyone remember it?</p>
<p>Yah justPhysics is right. black holes are like dead stars or some ****. Part of star process I guess. Not like the Princeton review in its 500 pages of entirety talked about it once… The force is going to be just from gravity on the incline, which is mgsin(theta) downward. take out m and the a is gsin(theta). Acceleration will not vary at all unless you have a changing force, like if r changes in coloumbs law or x changes in force of spring F of s = -kx. Hence the reason why the test writers said what is the “magnitude” of the acceleration. Those tricky bastards haha.</p>
<p>JustPhysics, could you explain the electroscope thing?</p>
<p>@cobalt60 do you mean the one where water is cooling and the temperature it will be when it is 8 seconds? I put 20 degrees… not sure at all if it’s right though.</p>
<p>Also for the question that asked what the rate was, I got 20 degrees per hour? was that an answer choice?</p>
<p>The chart was approaching 30. The wheel one would measure the force of static friction. I can’t remember what the picture looked like, but I remember that i was very sure of that one.</p>
<p>@lala Yes, 20 degrees per hour.</p>
<p>Can anyone confirm the quasar question?</p>
<p>lala love. It would be 30, since each hour or whatever the x interval was was halving the difference from 30, like 50, 40, 35, 32.5, and so one for 8 hours. Ca’t remember what this is called in math again. Horizontal asymptote.</p>
<p>noo~~~ :[[ </p>
<p>i got quasar for the star q</p>
<p>im so sad… so sad about this test.</p>
<p>so sad.</p>
<p>@lalalove7 yeah,it is. I don’t remember clearly.I was confused! which equation did you use?</p>
<p>Wait I think we’re talking about different questions benevolent…</p>
<p>it asked if a block is pulled at an angle of 37 degrees or something what the acceleration of the block was or something…it didn’t have to do with an incline…and I don’t remember the question you’re talking about; are you talking about the one with graphs? I’m talking about a different q.</p>
<p>Also, are you sure it’s the force of static friction? That’s what I put but I am pretty sure it’s kinetic because isn’t it like just sliding not like a tire of a car…?</p>
<p>I have a baseball game but I can type out an explanation for the electroscope then. Sorry.</p>
<p>What about the half life question? </p>
<p>Also what is this 30 and chart thing you’re talking about.</p>
<p>What are you talking about… The chart was approaching 20</p>
<p>i think i got something like 45 mins or sth for the half life</p>
<p>Quasar is not in star life. Black Holes occur when force from mass of star overcomes resistant forces of atoms and collapses inwards. </p>
<p>Half-life was 1 hr, 20 minutes. It went from 96 to 12, in 4 hours (12pm to 4pm).</p>
<p>Hr 0 - 96
1 hr 20 minutes - 48
2 hr 40 minutes - 24
4 hr - 12</p>
<p>Screwed up the hammer/bell question, forgot about gravity. It takes 10N to raise 1kg, 1 meter. So 5 meters * 5 kg * 10N = 250 J. I forgot gravity’s acceleration and put 25 J…</p>
<p>Anyone remember any other problems?</p>
<p>For the question regarding the velocity of the object orbiting earth. Do you remember what the distance was explicitly stated to be? I remember it was in km not m, so you had to convert, but I think I might have messed that up. I know i had the right denominator though (24<em>60</em>60), since it was m/s.</p>
<p>I think the distance was 1000km and it had to be meters</p>
<p>Also, where was the net gravitational force greatest and least?</p>
<p>Anyone remember that odd problem where it said something like </p>
<p>“For an object at at an instant accelerating at a constant, all of the following could be zero except:”</p>
<p>I chose “net force”, because theoretically, if the force had just been applied the other quantities: velocity, momentum, mass?, something else, could all be zero?</p>