<p>did anybody which point b/w the earth and the moon has the greatest, least, and zero net gravitational force?</p>
<p>As for the velocity of the cart, I believe it is 3 m/s, since in elastic collisions with same mass, the speeds of the objects just switch.</p>
<p>@justphysics
I agree w/ rohit13. You don’t have to show colleges how many times you took a subject test. So… how about you first see what you get and then take it again if you need to?</p>
<p>I signed up for the november physics test when I was signing up for my october one just so that i know i can fall back on it if the october one doesn’t go well.</p>
<p>for the velocity of the cart in an inelastic collision, i got 3m/s too i think</p>
<p>Thanks for the suggestions guys/girls; I will consider it. Here is a list I have compiled…help me out with the ones I said does anyone remember this question please</p>
<p>Also what about those mechanics questions with the time it took drop from a 45M building…3 seconds right? What about the distance across that some projectile goes?</p>
<ol>
<li> Final velocity of cart 3 m/s</li>
<li> Two different sized ropes: speed decreased wavelength changed frequency constant</li>
<li> Work to get rider up to bell: 250N</li>
<li> Rider has maximum velocity on the way up at point 1</li>
<li> The maximum net force: point A</li>
<li> The net force 0: point D</li>
<li> Rotating wheel: Static friction (I am positive now)</li>
<li> If amplitude of spring is change period remains the same</li>
<li> Light can be seen from all regions</li>
<li>White light at 6 only</li>
<li>The car on the loop has velocity sqrt(2v)</li>
<li>8000N for weight of person </li>
<li>Graph A vs. B^2</li>
<li>Object has constant acceleration net force can’t be zero</li>
<li>80m/s speed of wave</li>
<li>Lighting listening 3000m</li>
<li>Photoelectric, green light, orange light I and II</li>
<li>Efficiency of engine 0.6</li>
<li>Neutron can approach nucleus because it is neutral</li>
<li>Block’s acceleration when pulled at angle: a = (FCos(theta)) / m</li>
<li>Electroscope leaves increasing only</li>
<li>Voltmeter in parallel; ammeter in series</li>
<li>MR the change in kinetic energy is zero</li>
<li>Zero and Zero (was this two questions?)</li>
<li>Zero and Zero(was this two questions?)</li>
<li>Optics diagram: smaller and on same side as object</li>
<li>The angle light slowed down in water, having a smaller angle with regard to the perpendicular</li>
<li>The angle of incidence equaled the angle of refraction reflecting of the piece of glass</li>
<li>Energy is NOT a vector</li>
<li>Block up incline: Acceleration constant slope</li>
<li>Block up incline: Velocity had V shaped graph</li>
<li>Block up incline: upside down parabola</li>
<li>Two particles with different velocities between parallel plates: Same charge</li>
<li>Velocity of something around earth: V = (2(4.2 * 10^7) / (they made the period up I think because there was only one answer choice with the correct radius that they gave you))</li>
<li>Total resistance of 6 ohms: 4ohm and 12ohm in parallel, and 3ohm resistor</li>
<li>Area under F vs. x graph: work or potential energy (was work an answer choice?)</li>
<li>The magnetic field in the hoop (of the two hoop system) to the right</li>
<li>The energy was infinity NOT mc^2</li>
<li>Star thing: quasar (does anyone have a source to corroborate this?)</li>
<li>The chart approached 20 NOT 30 (it was pretty obvious, having a horizontal asymptote)</li>
<li>Half life 1 hour 20 mins</li>
<li>Current induced was I and II.</li>
<li>Inelastic cart speed was 1.5 m/s?</li>
<li>Bohr model: a few particles directed directly back</li>
<li>Specific heat was 2?</li>
<li>The impulse is equal to the change in momentum of the cart</li>
<li>2 times the amount of force (anyone else remember this question?)</li>
<li>The tension in the rope was 2M where it was holding up a pulley with two equal masses (anyone else remember this question).</li>
<li>The force diagram in the lower block had tension up and mg down.</li>
<li>8N of tension in rope (anyone else remember this question?)</li>
<li>Momentum has units kg * m/s.</li>
<li>A magnet is pulled through a coil with north first; it is then reversed with south first: the current flows in the other direction.</li>
</ol>
<p>Also any other questions that people remember…</p>
<p>The energy for an object near the speed of light is not infinity.
It is E=mc^2/(sqrt(1-v^2/c^2))</p>
<p>The rotating wheel is kinetic friction. If it was static friction, the object will try not to move away from the wheel, so it will rotate with the wheel. If you stack two books on top of each other and push the bottom book, the top book will move due to static friction. If it had kinetic friction, the book would start to slip off the book. The same for the wheel, the object is not rotating with the book so it is essentially slipping. The kinetic friction is trying to move with the rotating wheel, so it points towards the left while the tension from the string prevents this. The tension is equal to the friction, so it measures the friction.</p>
<p>I think the specific heat was 20 not 2 because the number at the top was multiplied by 10^6 while the number at the bottom (denominator) was 10^5.</p>
<p>Also I think the curve might be like 55 considering how hard that test was…anyone know how the curve is calculated?</p>
<p>There was also a problem about two parallel wires and a current going through both of them. The current went in the same way, so the magnetic field between the two wires is in the same direction.</p>
<p>I don’t remember the specific heat but I don’t remember 20 being an answer…</p>
<p>I still think it is static friction…but no sense in arguing</p>
<p>here is a post about the energy for an object near the speed of light…i don’t now if it’s true though…
I trust special relativity is not too much for a layman as it only requires simple arithmetic.</p>
<p>If we look to the energy of a moving body as we approach light speed we must use this formula </p>
<p>E = mc^2 / ( 1-V^2/c^2 )^.5</p>
<p>Close inspection of this equation reveals that as V approaches c the bottom half of this equation becomes zero hence the energy required becomes infinite.</p>
<p>I put mc^2 is that wrong…was mc^2 / ( 1-V^2/c^2 )^.5 a choice?</p>
<p>I think you mean the current when in opposite ways…if they went in the same way they would be in opposite directions…</p>
<p>Approaching infinity, not infinity itself. I believe it asked for what it was near the speed of light, not at the speed of light.
Yes, mc^2/(1-v^2/c^2)^0.5 was choice E</p>
<p>I am sure that 20 was among my choice of answers, I wasted some time on that question.</p>
<p>Eh yeah… probably current went in the opposite direction. I just remember that the magnetic field was the same direction.</p>
<p>Wow. ^This is actually really helpful</p>
<p>But I think I’m close to 800 failure now though. i forgot that I screwed up voltmeter and I did greatest velocity 1 downward. Why would it be upward?</p>
<p>I dont remember 52 at all. I remember a weird question about double south ended permanent magnets or something. Do you guys know what I am talking about? Also, do you guys remember charge going through capacitance where it was 9V and there was a battery and it asked for force? I think I am 6/9… probably more…</p>
<p>It would be upward because when it striked the bell(?) it made a sound, which means it had more energy than necessary to hit the bell. It was faster in the beginning. After it lost energy from sound, it was accelerated by gravity. If it had never hit anything and we assume that no energy was lost due to friction or air resistance, then the speed coming up and coming down at that height would be the same.</p>
<p>do you guys remember the question with the capacitor?</p>
<p>Hey, what abt the magnet w/ both ends attracted to the north end of abother magnet? Anyone knows/rmb the answer?</p>
<p>i don’t know if someone answered the Stars question which was an absolute joke.</p>
<p>but I got Black Hole as being not involved in the process… I looked up what the **** a quasar is and got :</p>
<p>‘Quasars are extremely luminous and were first identified as being high redshift sources of electromagnetic energy, including radio waves and visible light, that were point-like, similar to stars, rather than extended sources similar to galaxies.’</p>
<p>haha I have no clue if that means they are involved with Stars because they have something to do with redshift and redshift was an option…</p>
<p>:( test was a killer… I left about 8 and must have gotten 10-12 wrong… can I get over 750?</p>
<h1>1 and #43 were for the same little section. I got 3 m/s for the elastic collision and 1.5 m/s for the inelastic (the second question)</h1>
<h1>48 yup I remember, it was 2W because the pulley was massless and had two weights of W below it</h1>
<p>anyone else about the magnetic field for the question with the two loops? I said it had a current opposite to the hoop on the left, and went to the left…</p>
<p>I am NeuPhysics and I WILL ANSWER ALL QUESTIONS!</p>
<p>wait number 48 with the pulleys. What was the question asking for again?</p>
<p>Was it about the tension in the string with 2 equal masses on either side of the pulley?</p>
<p>I believe the answer is W. If you don’t believe me: </p>
<p>[Atwood’s</a> Machine](<a href=“Atwood's Machine”>Atwood's Machine)</p>
<p>@inject I am fairly certain it was 2W, because it asked for the tension in the string ABOVE the pulley that connected it to the ceiling. Not in the string connecting the two weights. It was a trick question, in my opinion.</p>
<p>@kdengg I also got 3m/s and 1.5m/s.</p>
<p>@bookbuddy I think I said the bar was a temporary magnet, or something along those lines. Not sure about that one though. Anyone else get the magnetic bar question?</p>
<p>@ambitious2, I haven’t taken the test yet (I’m taking it next Sunday) but if I got the q right, the tension is W. If the system is in equilibrium, the forces are equal on both sides,
meaning, T - W1 = W2 - T. Since we have equal masses, T = W. </p>
<p>I hope the Sunday test isn’t as hard as this one :/</p>