<p>@pckeller
It would be hard for me to give you the exact reference out of the 3000 SAT official math questions(if I do stumble on it again I will definitely give you the year and month of the exam), but I believe that the question had to do with the understanding of the concept of the line of symmetry. One had to recognize that the y-coordinate of the points, that are the same distance on both sides of the line of symmetry is identical. </p>
<p>Other than that, the interpretation of the equation of parabola y = a(x-k)^2 + k, in terms of shifts of y=x^2 and its relationship to the vertex (h,k) is another important idea. And of course, the fact that they are testing this particular question in the question of the day, definitely means that this idea is fair game for the SAT. </p>
<p>Second Method(does not require knowing the actual equation of the line of symmetry):</p>
<p>If we know that the parabola attains its maximum value at x =2, then the value of y at x = 1 and x=3 would be identical, these two points are the same distance from the axis of symmetry. One could also choose, x = 0 and x = 4, which actually might be more convenient because of x = 0 as one of the points. </p>
<p>If we replace x with 0 in the quadratic equation y= -2x²+bx+5, we obtain
y = 0 + 0 + 5 = 5, </p>
<p>because at x = 4, the y-coordinate of the parabola is identical, when we replace x =4 in the above equation of the parabola we must have y=5, therefore:</p>
<p>y = -2(4)²+b(4)+5 = 5 </p>
<p>or -32 + 4b + 5 = 5 </p>
<p>or -32 + 4b = 0 </p>
<p>or 4b = 32 </p>
<p>and again we obtain b = 8.</p>
<p>Third Method(Algebraic method by completing the square):</p>
<p>Another way to approach this problem would be to complete the square:
y= -2x²+bx+5</p>
<p>y = -2(x² - bx/2) + 5 </p>
<p>y = -2[ (x - b/4)² - b²/16] + 5 </p>
<p>y = -2(x - b/4)² + b²/8 + 5 </p>
<p>Here the expression (x-b/4)² is always positive(square expression), therefore
-2(x - b/4)² is always negative. The largest value of y will be attained when this expression is zero, which would happen when x - b/4 = 0 or x = b/4, we are given that this happens when, x is 2, which again leads to b = 8. </p>
<p>This approach is longer because we are redoing all the work to show that the parabola y = ax² + bx + c, attains its extreme value at x = -b/2a. </p>
<p>Cheers</p>