<p>Hi,</p>
<p>Here’s a few homework problems I’m having trouble with:</p>
<li>What number of moles of O2 is needed to produce 14.2 grams of P4O10 from P? (molecular weight of P4O10 is 284)</li>
</ol>
<p>2.
3 Ag(s) + 4 HNO3 < – > 3 AGNO3 + NO(g) + 2H20
The reaction of silver metal and dilute nitric acid proceeds according to the equation above. If 0.1 mole of powdered silver is added to 10.0 mL of 6.0 M nitric acid, the number of moles of NO gas that can be formed is</p>
<p>A. .015 mole
B. .02 mole
C. .030 mole
D. .045 mole
E. .090 mole</p>
<p>Thanks in advance,
Joe</p>