<p>you had to write out the metathesis reaction that happens and then use reaction stoichiometry, get the moles of MgCl2 then find mass and divide by total mass and voila --> answer.</p>
<p>what did u get for 3f and 3b?</p>
<p>thanks.....</p>
<p>-360kJ and 71000 M^-2 s^-1 (that might be the wrong number of 0's but it was big, and had a 7 and a 1)</p>
<p>i think that is too many zeros.... hmph not doing the problem over lol.</p>
<p>for 3b...dont you use G= -nfE..so G=- 6x96500x0.62</p>
<p>yeah mv senior. it was 6 x 96500 x .62.</p>
<p>i thought it was 5 X96500X.62</p>
<p>For problem 1a, I think the answer was actually kp = P(CO)^2 / P(CO2). The carbon is a solid and therefore does not affect the pressure.</p>
<p>I think it was 7100</p>
<p>I did fine on it I guess....except I still have no idea how to do the ionization energy equation thing...very basic but I somehow neglected while studying</p>
<p>me too, because i think i put 7.10 x 10 ^3</p>
<p>and mflevity you're right, solids dont matter in the equilibrium expression.</p>
<p>yeh stephennn...the -360 Kj is correct and so is 7111.11 correct</p>
<p>I had NO idea how to do that ionization equation either. I guessed and put </p>
<p>F yields F+ and e-</p>
<p>was the forumula for hydrate 5?</p>
<p>i got 2 as the hydrate ratio =/</p>
<p>hey guys
does anyone know how to do b</p>
<p>i got x 6H2O.... i think as long as its consistent with the number of moles you found of water though, you'll get credit.</p>
<p>to do 2b theres a bunch of subtracting and stuff. ill get a headache if i do it again lol.</p>
<p>I got MgCl2 * 6H2O</p>
<p>i did same thing forionization enrgy as you ptranium</p>
<p>for 3 b, is it points off if not in Kj?</p>