2011 January SAT: Math

<p>which one was math experimental? was it the one with the 50/51?</p>

<p>so wait, for the radios is it 2/5 or 3/5,
i put 3/5, then changed it because it said after picking a non-defective, then also picking a non-defective afterwards, so 4/6 x 3/5?
■■■■ dont tell me i got -2 >< ahhhh</p>

<p>Each overlap reduces the length by the length of the overlap. The thing was reduced by 8 inches; there were 4 overlaps, so each was 2 inches.</p>

<p>I’m with garfield. I counted the overlaps in the picture and then divided the amount shorter it was by that number. 8/4=2</p>

<p>Just drew it out and worked it. Makes sense now. I read too deep into the question. Thanks! There goes my 800 :(</p>

<p>I think if collegeboard chose not to stick the word ALSO into the radio one, it wouldve been much more clear…
the overlap i got 2
slope i got -4
1080 for eggs
i hope i changed 49/50 to 50/51 at the last second :
btw, you guys think that collegeboard would change that question to either answer because of the lack of clarity in that question? :S
has it happened before when they were like spammed w/ emails saying they were wrong?</p>

<p>well im gonna take the SAT again for sure, any advice on what test book to use when blue book is exhausted?</p>

<p>YES bigdreamer, that’s exactly what I did!
omg I need to get this one right. I will be so ****ed if I don’t get an 800 just cuz it was wasn’t worded correctly.</p>

<p>Anybody remember the MC question where you had to find the area of a cube, given that two 45-45-90 triangles made up a side and the hypotenuse was radical 2? I got 1.</p>

<p>I have a question about a problem that said: the perimeter of a triangle and one of the sides of that triangle (x) is equal to the average of the other two sides. Find x in terms of P.</p>

<p>Did I read the problem wrong or something? I interpreted it as:</p>

<p>P + x = (a + b)/2</p>

<p>Where a and b are the other two sides. But then you get x = -1/3P which, as well as making no sense, wasn’t an answer.</p>

<p>i got one too dre2001!</p>

<p>It’s x=1/3P You probably switched the sign somewhere</p>

<p>what free response math question had the answer 1/3</p>

<p>Yeah, that was correct. 1, 1, sqrt(2) right triangle. 1^3 = 1</p>

<p>i think i got 2/3 for that triangle one…not sure though</p>

<p>silenex, the best way is to just replace x with a number, like 3. that means the other 2 sides are 2 and 4 as they avg. out to be 3. so the perimeter is 2+4+3=9. 3/9= 1/3</p>

<p>can someone please answer
what was the 1/3 free response question!?!?!??!
PLEASEEEE</p>

<p>debater and dre it was 1
silenex, x = (y+z)/2 2x = y+z
x+y+z = P
x + 2x = p (substitution)
3x = p
x = (1/3)p</p>

<p>■■■ - 80 on the psat -5 on this math section, do you think ill be 700+</p>

<p>That’s what I put, actually. I reasoned it out without the math and got that, so I figured that I must’ve switched the sign. But when going over it (now) I can see the math works out to (-1/3)P. So I must be interpreting it incorrectly?</p>

<p>here’s what I’m doing:</p>

<p>P + x = (a + b)/2
2(P + x) = (a + b)</p>

<p>a + b + x = P
a + b = P - x</p>

<p>plug into:</p>

<p>2(P + x) = (a + b)
2P + 2x = P - x
3x = -P
x = -P/3</p>

<p>somebody
1/3 free response question
IM LOSING MY MIND HERE</p>