2011 January SAT: Math

Test Preparation SAT Preparation
421

<p>Does anyone remember the question about the two squares on top of each other?</p>

422

<p>for that one question about minutes and hours, was the answer C, 80?</p>

423

<p>@tangled – Yes, that’s what I got.</p>

424

<p>^^
It was sqrt5-1/2</p>

425

<p>(sqrt5-1)/2 - experimental
time i remember being 8:40 - 11:10 which was C</p>

426

<p>(sqrt5-1)/2 was not experimental, unfortunately. :P</p>

427

<p>Which time question was 80?</p>

428

<p>How do you know which was experimental?</p>

429

<p>hmm darnit i can’t remember what i put… does anyone remember the exact problem by any chance? im starting to panic…
(the two squares problem)</p>

430

<p>@zkaplove17 – It was something about two machines, one which produces something 6 units in an hour and one which produces 8 units in an hour or something like that, and the difference between them to produce a certain amount of units in minutes.</p>

<p>The numbers I put there aren’t exact as far as I know, but hopefully that jogs your memory.</p>

<p>EDIT: As for knowing what’s experimental, if everyone has it it’s not experimental.</p>

431

<p>As far as I know…-1 and still 800 is very rare.</p>

<p>@titration I can draw a picture of it, hold on</p>

432

<p>Don’t panic it was one square on top of another. There was a line that bisected a side of the large square and formed a triangle. Through 45-45-90 and 30-60-90 triangles you can deduce it, i’m not sure how to explain it any way else?</p>

433

<p>For x and w:
x = 2y
y = w/3</p>

<p>So x = (2/3)w
and x^2 = 4/9w^2
therefore w^2/x^2 = 9/4?</p>

<p>!@#$%^& I put 4/9!</p>

434

<p>The 9:4 question was primarily confusing for one reason: you were given X before W, so you would think it would ask you for the ratio of x:w. But it asked for w:x, which I am sure many people just skipped over or didn’t realize. I didn’t until I was about to write my answer down as 4:9 and realized that it was asking for the ration of w:x.</p>

435

<p>Thank you OSU, it was (32 x 10) - (32 x 7.5) = 80</p>

436

<p>you can also just use a^2+b^2=c^2</p>

437

<p>Okay here’s a picture of the problem I quickly made on Paint:
<a href=“http://i51.■■■■■■■.com/8vn9rr.png[/url]”>http://i51.■■■■■■■.com/8vn9rr.png&lt;/a&gt;
I don’t remember how exactly it was labeled but it’ll serve its purpose.
So basically the problem was you had to find what FA was, and you were given the length of the bigger square as 1, that E was the midpoint of AC, and that BE was the same length as FE. </p>

<p>Since E is the midpoint, AE=1/2.
You use the Pythagorean Theorem and find that BE is Sqrt(5)/2, thus FE is Sqrt(5)/2. Then you subtract 1/2 to find FA. So the answer was (Sqrt(5)-1)/2</p>

438

<p>Upon discussion of the SAT i learned that I had 4 math sections and my friend had the same sections as me exactly except for section 6 which contained the c and n+5 question and the (sqrt5-1)/2 question, instead he had a critical reading section then that I didn’t have. I am not sure completely how variable works but it seems that that was the variable.</p>

439

<p>was 80 even a problem?? i dont remember it…?</p>

<p>@canbambiswim thanks i just dont remember the given measurements and what we have to find…</p>

440

<p>Which grid in had 16 as an answer?</p>