4 Questions on the December SAT Math

<p>I don't think I had the toothpick, I had the diameters bisecting, I had xyz, I had the 10 rt( 2), I had the trapezoid= rt(h^2+25), I had the median, mode, average problem, umm....that's all I can remember right now...</p>

<p>I had those problems too.</p>

<p>All I remember is that the 110 one was a grid-in.</p>

<p>I think the one with the toothpicks was my experimental sections, and I believe this triangle problem was also in it. But I'm sure I got it right. I checked it two ways to see if all the angles add up to form 180/360. I'm not sure if 110 was my answer though, but it sounds familiar.</p>

<p>Yeah for the triangle one, I remember I was really sure about 110. People are saying something about angles of 142 and 108, right? Well I remember getting both of those and then realizing that 142 was wrong for some reason, then I figured out another way to do it and got 110...I did something with calculating supplementary angles or something...</p>

<p>Haha, this is such a blur...</p>

<p>Oh and for the bacteria one, did anyone put (1+r/100)^4=2?</p>

<p>I put that ruella! I just made the left side of the equation 50 and the right side 25(1+r/100)^4. Then, I just divided by 2. I hope I made the correct assumption in saying that 25 was the original population and that 50 is the new, doubled pop.</p>

<p>Yep it did =2</p>

<p>25*blah= 50</p>

<p>blah=50/25
blah=2</p>

<p>um guys...the 18 and 81 question...was that in the first grid in or the second....please tell me it's the second one because i didn't finish the last question of the second one and i'm hoping that's the experimental...(the last question of the last grid-in section was about some cone thingy...and since the proctor didn't call time i spent too much time double checking the second the last....grrrrrr</p>

<p>The answer was 29 and 92, 92-29= 63, it asked for the largest, 81-18=63, 29> 18, so 29 is it.</p>

<p>Let's keep it going :P</p>

<p>I got 110 too</p>

<p>omg if i put 120 i will be so mad. oh crap i think i did.</p>

<p>i found out htat the angle was 70 degrees. crap... idiot. 180-70 = 110 not 120. Oh well</p>

<p>I hope the curve will be good like -1 = 800
Hahaha, but it didn't sound like too many people thought it was difficult..</p>

<p>for some reason i thought it wasn't that hard, except for like one or two, especially that bacteria problem, no clue wut it was asking</p>

<p>Did the H/m one ask for h in terms of M or M in terms of H? Anyone program it in? Please?</p>

<p>Pretty sure I plugged crap in and got the right answer but if I misread it that would be quite bad</p>

<p>It was m in terms of h.</p>

<p>Then 60h indeed, not h/60 as a few said earlier...</p>

<p>I got II and III for the xyz</p>

<p>I cant remember the others =[</p>

<p>DAMMIT, I put 18 on that one. Oh well</p>

<p>It was definitely I II III on XYZ because to be odd all three of the factors must be odd...</p>

<p>^was that part of a grid-in section ????and if so...which one?...is that the one with the last cone problem or the 92-63=29 one?...or are those all in one section?......>_< i had two grid-in!!!!!!!!!!!!!1</p>