<p>What did you think of 59 ? That was the trickyist act question ever.</p>
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<p>The angle in the triangle with the two congruent circles was 30. cuz if u see, the 3 sides are congruent. </p>
<p>and damn, i got the log questions wrong. ugh…
that the last page in math was hard …</p>
<p>So far, it seems I’ve gotten the log one wrong, but that might be it. I did guess on maybe two others I think. </p>
<p>Oh…what about the compound function one. I thought I did it right, but it never seemed to work. I think my answer had something to do with 1 and 2, one of those was negative I think.</p>
<p>What did you guys get for the question that was about 6/9a. I got kind of confused on this one and didn’t want to spend too much time so I put A (it must be rational) and decided I’d come back if I had time (I didn’t for once).</p>
<p>Other than that it seemed pretty easy, I had to guess on the last two because I ran out of time (I added wrong initially for one of the tables), but I’m nearly positive I got one right and one wrong. I could live with a 34-35 though… it’s much better than the 31 I got in April.</p>
<p>It must be rational, that is the only constraint. By definition a rational number is made from a ratio, so as long as the individual components are rational, it is still a ratio.</p>
<p>x=2/3</p>
<p>I’m nearly positive.</p>
<p>edit: I just realized how I ****ed up…dammit.</p>
<p>@vgfanatic2 I think it wasn’t x must be rational because if you plugged in 1/3 you still got a real number.
I put x must be 2/3 or something</p>
<p>Overide was right </p>
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<p>Overdrive is right about 6/9x question</p>
<p>the intersecting circles had to be 60 degrees. the three radii formed a triangle.</p>
<p>Intersecting circles was 30!!!</p>
<p>what was the radius of the circle where the 3 points where all touching it. I got 5</p>
<p>never mind it is 30 I read it wrong</p>
<p>there was also a question with a right triangle where M and N lie on the edge of a single circle and you had to find the radius</p>
<p>I put 5 because the triangle was a 6/8/10, with 10 as the diameter</p>
<p>@caveboy</p>
<p>Im pretty sure it was
x/2 - 1</p>
<p>@brownguy that was a different question but I do remember getting that answer</p>
<p><a href=“http://i.imgur.com/HmQPs.jpg[/url]”>http://i.imgur.com/HmQPs.jpg</a> what was the answer to this question guys? Last question? </p>
![http://i.imgur.com/HmQPs.jpg[/url]](http://i.imgur.com/HmQPs.jpg%5B/url%5D){kind=link}
<p>I guessed K</p>
<p>The radius of the circle between the three points of a triangle was 5. The height of the triangle was 4.8 while the base was 10. The point that made the height was offcenter slightly, so it made up for the last 0.2.</p>
<p>the radius if 5 because its an 6/8/10 triangle, and if a right triangle is inscribed the hypotenuse is diameter. so 10 is diameter, 5 is radius</p>
<p>@Imdad</p>
<p>I’m pretty sure that was abs(x^2 - a) [I forget if it was a or a^2, though it is irrelevant). I just guessed that because I ran out of time, though I graphed it later and it was right.</p>