<p>The Falcons won 15 of their first 20 games. Assuming they win only half of the remaining games how many more games must they play to have won 60% of all their games.</p>
<p>If you could please explain the answer - thats if you can get it, I don't see how anyone could get this. Mabye its me, mabye its the problem.</p>
<p>so it (15 + .5y)/(20 + y) = .6 (y stands for number of future games)
15 + .5y = .6 (20 + y)
15 + .5y = 12 + .6y
3 = .1y
30 = y</p>
<p>Falcons won 15, lost 5 games.
15 more games won and 15 lost make
won = 30, lost = 20, total # of games = 50
60% of all games won.</p>
<p>Eidt.
Jshapiroro105 just beat me to it. :(</p>
<p>Thanks, I’ve been scanning through this algebra book to brush up and find my weaknesses. Well for some reason problem solving is my absolute hardest. Even after you explained it, although I understand the problem, I don’t feel I made a connection so that I may apply this concept to problems in the future.</p>
<p>The confusion lies in the equation. Would 15/20 + .5x = .6 have been wrong? I say this because could not .5x/x be represented as simply .5x? Wouldn’t this change the result of the equation?</p>
<p>Bump… .</p>
<p>I’m not really sure what you are asking but .5x/x = .5, not .5x</p>
<p>That was my question thank you. I should have taken pre-calc in my senior year of high school rather then blowing it off by taking a remedial class. Although looking back at it I had some good times in that math class, I actually looked forward to the “show” that would be presented by the “trouble-makers”.</p>