<p>A circle with center O is tangent to the x-axis and the y-axis. The circle has a radius of 1, and is tangent to segment AB at point t. Segment AB has a slope of -1. What are the coordinates of t?</p>
<p>a. (1,1)
b. (square root(2), square root(2))
c. (1+square root(2)/2, 1+square root(2)/2)
d. (1+square root(2), 1+square root(2))
e. (2,2)</p>
<p>ITS A MONSTER....but to those who want to know, I will post the answer after some give it a shot. ;)</p>
<p>lol its not that hard ........</p>
<p>i thought it was.....its one of the ones i've gotten wrong in the math, and i barely miss one or two per section. besides, even after looking at the answer i had no clue how to do it.</p>
<p>i don't think it's a SAT l math problem.....is it?</p>
<p>C, isn't it? make a 45-45-90 triangle</p>
<p>Yeah it does seem pretty hard. Cause to me the segment can go anywhere.</p>
<p>cant the segment go through multiple places o.o</p>
<p>answer is C....i am pretty sure</p>
<p>liebenasuka, u're right.</p>
<p>and yeah it is an SAT I math problem. way too difficult...if i ever got that on the SAT i could kiss my 800 goodbye.</p>
<table><thead>
<tr>
</tr>
</thead><tbody>
<tr>
</tr>
<tr>
</tr>
<tr>
</tr>
</tbody></table>
<p>Since slope is -1, cant it go to any of these places?</p>
<p>ahh damn spacing</p>
<p>it's a monster alright....i used calculus......anyone know any easy method?</p>
<p>The answer's C, I'd say. MrPrez, the segment is tangent to the circle at point t. It's slope is -1. That leaves only one place for t to be.</p>
<p>gluttony, im jealous of ur calc...too bad i havnt taken calc yet...but i am taking AP Calc AB and BC this year.</p>
<p>lieubensuka...please explain your method...mine is too complicated (it takes a lot of time,i had to find out the equation of the circle,then i differentiated it to get the tangent and i put the value -1 to the equation to find out a relation between x and y and then solved the equations of the circle and the tangent....pretty big,took me 2 min 41 second)</p>
<p>I don't think I used calculus I just thought about it. Well yeah, you have to know the unit circle maybe, or 45-45-90 triangle measurements.</p>
<p>^ but the segment can go through the axes as well and still be tangent to the circle.</p>
<p>u guys want me to type up the explanation?</p>
<p>Not very hard at all... give me a second to write explanation.</p>
<p>EDIT: Screw it, just type the official one.</p>
<p>It has to have a slope of -1.</p>
<p>EDIT - it's not all that hard. You guys might be overthinking it.</p>
<p>The key is to realize that the answer must be on the circle. C is the only one that fits that requirement if you work it out.</p>
<p>In other words it must satisfy</p>
<p>(x+1)^2 + (y+1)^2 = 1
(x+1)^2 + (y-1)^2 = 1
(x-1)^2 + (y+1)^2 = 1
(x-1)^2 + (y-1)^2 = 1</p>
<p>with x=y</p>
<p>C is the only one that will fit if you plug the answers in.</p>