Another "blue book" math problem (p. 532)

<p>I'm having a hard time figuring out this equation in number 6 on page 532 of the blue book...</p>

<p>How do you solve the equation for m^-1 ??</p>

<p>Thanks for all replies!</p>

<p>A negative exponent--> inverse. m^-1= (1/m)--> inverse of m.</p>

<p>rewrite the orininal equation as (10m^2)/k = 100m</p>

<p>so (10m^2)/k = 100m
10m^2=100mk
m=10k
m^-1 as K
1/m
1/10k
D</p>

<p>Thanks a lot!</p>

<p>I did it a (slightly longer) way:</p>

<p>10m^2k^-1 = 100m, square root both sides and you get
sqrt(10) * m * k^-1/2 = 10 * sqrt(m)
You know that a number to a negative fractional exponent is equal to its reciprocal so....
1/sqrt(k) = 10<em>sqrt(m)/sqrt(m), square both sides...
1/k = 100m/10m^2, now divide
1/k = 10</em>m^-1
m^-1 = 1/k*1/10
= 1/10k</p>

<p>Hey guys, sorry to revive an old thread but I need help in understanding something. I understand everything until how you simplify 10m^2=100mk. If you could explain that it would be awesome, thanks!!</p>

<p>divide both sides by 10 -> m^2=10mk
divide both sides by m -> m=10k</p>

<p>I don’t know the problem, but it looks like you are trying to express 1/m in terms of k. If that’s the case then,
1/m=1/10k
which you can show by dividing out each side by each of the terms. in other words dividing both sides by 10k is m/10k=10k/10k => m/10k=1
then dividing each side by m gives m/(10km)=1/m => 1/10k=1/m.</p>

<p>Oh wow lol brainfart, thanks.</p>