<p>Its been said here already, but our teacher is basically telling us to study Hardy-Weinberg a lot, because she and others think it will be a FRQ</p>
<p>Okay, usually they dont have free response questions on specific systems. The questions usually evaluate a certain thing common to multiple systems in the body.
I also noticed on College Board that they are very generous in their grading of the essays unlike with most other subjects.</p>
<p>it might not be about phosphorylation at all… it could be lab 4 too… or also about transport of materials… idk x</p>
<p>My guesses are either a lab 2 or 4 essay, so it could very well be on that lab.</p>
<p>I think they are generous on the essays because one of the AP Bio teachers at my school, who is a reader, said that average score on each FRQ is 2 to 4 points. Out of 9!</p>
<p>^
i don’t think its because they are really strict.
its more because the free response questions are really hard. the syllabus is so wide and there’s bound to be some questions or areas you might no recall and have to leave unanswered…</p>
<p>“I think they are generous on the essays because one of the AP Bio teachers at my school, who is a reader, said that average score on each FRQ is 2 to 4 points. Out of 9!”</p>
<p>That’s what I’m hoping for. If I’m not mistaken, all AP tests are graded on curves. The greater the amount of clueless people who know little about biology, the better my chances.</p>
<p>I don’t it is very likely that there’ll be a Hardy-Weinberg question. Like someone previously said, it was on Form B last year, so it seems unlikely to be on this year. There’ll probably still be a couple of multiple choice on it though.</p>
<p>
</p>
<p>That doesn’t really mean anything last. Last year, the AP Chemistry Equilibrium question was on Kp, which had been on the Form B the year before. Sometimes, they just want to emphasize that a topic is important.</p>
<p>Hardy-Weinberg is not as important as Kp in their relative APs.</p>
<p>What’s Kp?</p>
<p>Equilibrium for Pressure. Chemistry calculates equilibrium constants and Kp is for pressure.</p>
<p>More specifically, for most Keq calculations you use molarity. But, for Kp you use pressure. So, if you have the reaction A + B –> C + D (where, say, A, C, and D are gasses and B is not), then Kp=(D)*(C)/(A). B is ommited because it is not a gas, and the parenthesis represent pressure (whereas brackets generally denote molarity)</p>
<p>i dunno what the past few years have been but i’m thinkin’ DNA synthesis braaaaaahs</p>
<p>in LAST year’s exams … didn’t even study for the FRQ’s so easy… I made some BS up for the lake productivity question[did not design lab AT ALL].</p>
<p>So to all those people scared to labs etc. never fear… the MC curve WILL SAVE YOU!</p>
<p>I did not practice labs at all(we didn’t do one single lab in class)…</p>
<p>^Did you get a 5?</p>
<p>
</p>
<p>Lucky, I like the labs, but not the tediousness of the lab workbook. My lab grades are so much lower than my test grades ahaha :/</p>
<p>
by that i, of course, meant transcription and translation, not the synthesis of the DNA itself</p>
<p>(:</p>
<p>:) @ poseur</p>
<p>Lol those essay questions were exactly what I did NOT thoroughly study.
My teacher was betting on circulatory system, water potential, and proteins.</p>