Hi,
So ive done this problem at least 5 times, check each step, and keep getting an answer different from the answer key. Can someone please do this problem from the beginning and fully explain it?
Here it is:
http://oi61.tinypic.com/120tugp.jpg
Thanks!!
My answer is .24
all you do is divide 11088 by 12487 and you get .86
then you divide 1759 by 12487 and you get .14
finally, you multiply 2(.86)(.14) = .24
the equation for the frequency of heterozygotes is pq+qp= 2pq
I got 0.47. My teacher administered this exam to us in class and gave us the answer key. I believe they accepted 0.46, 0.47, and 0.48
you divide 1759 by 12487 (the total number of birds) to get .1469. This is the proportion of the birds displaying the recessive phenotype and thus must have a recessive genotype. so .1469 = q^2. q = 0.38. so p + q = 1 so p = 0.62. 2pq = 2(0.62)(0.38) = 0.47, and 2pq represents the frequency of heterozygotes
@InstantEco Your error was that 11088 represents homozygous for dominant and heterozyous. Also, you need to take the square root to find p and q.
my bad, the correct answer is .47 Disregard my previous post.
q squared = 1759/12847 = 1.369
q = .37
p = .63
heterozygous = 2 p q = 2(.37)(.63) = .47
