AP Biology Multiple Choice Question

Test Preparation AP Sciences
1

<p>I'm taking the 2002 released exam (<a href="http://bensonapbiology.concordcarlisle.wikispaces.net/file/view/2002exam.pdf%5B/url%5D"&gt;http://bensonapbiology.concordcarlisle.wikispaces.net/file/view/2002exam.pdf&lt;/a&gt;)
and I'm a little confused on question 109:</p>

<p>Assuming that the population was in Hardy-Weinberg equilibrium for the G-locus, what was the frequency of allele G in the gray moths that emerged in 1980?
A) 0.33
B) 0.50
C) 0.67
D) 0.75
E) 1.00
The answer is B - 0.50 - but the graph shows that at 1980 the overall allele frequency is 0.50 so shouldn't the allele frequency in only the GRAY moths be higher?
Looking at question 108, since 2/3 of the gray moths are heterozygous (Gg), then 1/3 are homozygous (GG). So 1/3(1) + 2/3(1/2) = 0.67 or C.</p>

<p>I don't understand why the answer is B! Can someone please help?</p>

2

<p>Bump… Help please guys?</p>

3

<p>Well, I looked at the graph and my immediate answer was 0.5 since the graph shows Allele frequency G</p>

<p>The question imo is more of a graph interpretting question and doesn’t really require you to apply knowledge about hardy-weinberg equation or do any computation and such, so maybe when the questions asks for “frequency of allele G in gray moths”, they meant only “frequency of allele G”</p>

4

<p>Thanks! It just seems strange since some of the moths were gray and some white. But it seems like since it’s the Collegeboard they would have found the mistake and eliminated the question if it was just a badly worded question.</p>