So my bio teacher told my class that last month, the collegeboard said there will be no hardy weinberg calculations on the AP.
Can anybody confirm if what he said is true?
If he’s not right, can someone please explain the difference between p^2 and p.
Thanks!
I don’t think that’s true, hardy-weinberg principle is pretty important in AP Bio, my teacher said that there was a high chance of it being on there. And p^2 is the frequency of the homozygous dominant trait and p is the frequency of the dominant allele.
Thanks!
Also, just a quick question about Chi square.
The null hypothesis is chat your data will NOT be statistically relevant. If after all the calculations, X is greater than the critical value on that chart, then you reject the null hypothesis, meaning the data IS relevant.
^ Am I right?
P^2 is the percentage of homozygous dominant individuals and p is the frequency of the dominant allele in a population
lets say there is a flower that has a population with 16% white flowers and 84% red flowers
in this case p is .6 p^2 is .36 q^2 is .16 q is .4 you get the p values because p + q = 1 (all alleles sum to 1) you would just square root the q^2 to find the rest. (the square root of .16 is .4) also don’t forget p^2 + 2pq + q^2 = 1 (all individuals sum to 100% to find the frequency of heterozygotes its 2pq and frequency of homozygotes ( p^2 , q^2 )
Sounds right to me!
Thanks a ton guys, looks like I have all the Math down pat!
On to the information itself, how well would you guys suggest I know plants? By this, I mean their reproductive cycles, properties, etc.
Should I focus my time on practice essays and going over ecology, evolution, etc., or pretty much teach myself plants?
just skim over plants and go over ecology and evolution
Lol it wasn’t on there
How did your teacher know :o
That awkward moment when you try to cram last minute but then it basically feels like everything you studied all year wasn’t on the test.