<p>How many points do you guys think I would get on 6b if I messed up after separating and then finding the integral of the right side?</p>
<p>Non-calculator MC had some tough problems. I mainly ran out of time and had to guess on a few. Calculator MC was extremely easy. I was done early and had time to check all of my answers. The calculator FRQs were okay. I ran out of time on the last calculation for #2, so I just had to leave it as an integral. Hopefully I only miss 1 point because of that. The rest of the FRQs were relatively easy. Overall I though it wasn’t bad at all. Really hoping for a 5.</p>
<p>You might get the separation of variables point and MAYBE a point for integrating the right side correctly.</p>
<p>Those of you concerned with number 6 FrQ, check this out:<a href=“College Board - SAT, AP, College Search and Admission Tools”>College Board - SAT, AP, College Search and Admission Tools;
Look in the last page, it states a similar problem</p>
<p>Correct me if I am wrong, and I could be, but…</p>
<p>I’m pretty sure the Integral of 1/(e^y) is NOT ln(e^y).</p>
<p>If you take the derivative of ln(e^y) you have to account for the chain rule and does not give you 1/(e^y).</p>
<p>I solved it by making it e^-y.</p>
<p>So what did you get for c @adrLan</p>
<p>Whats the answer for 1c? Something about if gravel is increasing at t=5</p>
<p>I think I guessed on that one and said it wasn’t. Don’t remember what I put for the justification though. I wasn’t really sure how to think about it.</p>
<p>I got put in the very far corner where, of course, I couldn’t see the clock. Ran out of time on the noncalc MC and had to step up my game for the rest of the test. And, since I have such good luck, I’m also sick on AP exam week as well.</p>
<p>I said it wasnt too. Something about g(5) less than 100… But some people said increasing.</p>
<p>Did #6 only have two parts, a and b? I feel like I may have missed part of the question. It seems at that I would be so short.</p>
<p>@etisawesomez iirc I plugged t=5 into G(t) which was the rate of change in tons/hr then showed it was positive. maybe?</p>
<p>Except gravel was also exiting at 100 tons/hour. So even if it was coming in at 97 or w/e it was still being processed at 100 per hour so it was decreasing</p>
<p>@aptheking</p>
<p>Said the exact same thing!! Hope we are right!</p>
<p>I’m starting to get worried about the sep. differential equation question now. I said that the antiderivative of 1/e^y was lne^y, which equals y</p>
<p>Yeah, on the first one you had to take t=5 from G(t) - 100. Should have been decreasing.</p>
<p>^ I did the same! Anything that seemed easy, actually wasnt.</p>
<p>Now I’m pretty sure I failed :(</p>
<p>Does anyone know when they release the free response answers?</p>
<p>they shoudl post them on Friday</p>