<p>I cannot figure out this problem if anyone can help me figure it out</p>
<p>The following data is the age at death (in days) for infants who died from sudden infant death syndrome (SIDS). Construct a 95% confidence interval for the true difference in mean age at death for male and female SIDS victims. </p>
<p>Female 55 120 135 154 54 115
Male 56 60 60 106 140 147</p>
<p>Thank you for any help you can give me</p>
<p>I don’t know much about Statistics, but here’s a good source (it comes from an Ivy!!):
[Confidence</a> Intervals](<a href=“http://www.stat.yale.edu/Courses/1997-98/101/confint.htm]Confidence”>Confidence Intervals)
Confidence Interval = mean ± critical values*standard deviation/sqrt(sample size)</p>
<p>I hope that helps.</p>
<p>Good luck on AP Stats if you can’t do this, lol. Anyways, assuming this is a z-test(not a t-test), I got (-29.09, 50.419).</p>
<p>For means problems, use T-tests, not Z-tests. Z-tests are for proportions. Grab your calculator, put the data in a list, and find the appropriate function (this is calculator-specific; I won’t go through the steps for each TI calc, but you can google it)</p>
<p>I think everyone covered it pretty well but in case you still have any confusion, let me know! 
</p>
<p>I believe you are just supposed to take the mean of each and subtract one from the other (doesnt matter which first as long as you remember it and correctly interpret it). Then do the Standard Error calculations and find t* for the d (+/-) t* (SE(d)) where d is the difference in the means. Best of luck :D</p>
<p>Z-tests aren’t necessarily always about proportions…</p>