<p>Hey-- I was wondering if anyone could help me with this statistics problem</p>
<p>You are standing in the streets of NYC and you see 7 taxis drive by (405/73/280/179/440/301/218). Assuming all taxis are numbered 1,2,3......n, how many taxi's are there in NYC?? Do not use a confidence interval.</p>
<p>How do you solve this??</p>
<p>fairly easy, assume it's a srs... and average the 7 values... this will give you an approximation of the average... double it and voila that's the number of taxis, yes i realize conditions are not met for an srs, but it can be assumed</p>
<p>I think it should be double it plus 7. 0-6 are not possible answers.</p>
<p>im just shooting the moon but...</p>
<p>average it out, find the standard deviation, go 3 standard deviations up, and theres ur answer. although thats 99%, but its close enough...(?)</p>
<p>erase my last post. .. averagee*2. k0w's method is less acurate, but more statistically sound.</p>
<p>would K0w's method be considered using a confidence interval? Are there any other ways to solve this? (there are supposed to be 10 lol)</p>
<p>not necessarily i think ... they dont give u the standard deviation so im assuming its a t-test. a confidence interval is </p>
<p>mean +/- t*s/radn. </p>
<p>usually a confidence interval is something used to try to prove against a null hypothesis. i dont know why thats there, but o well. im just using the empirical formula as a basis.</p>
<p>Thank you so much for your help!! Any other solutions would be accepted as well :)</p>
<p>find mean/2...(total/7 *2) </p>
<p>This answer still sounds the best to me. The other way is a confidence interval and think about it. If you find the mean thats the average of a random sample. Considering it reflects the population, you would assume that the size of the population would be twice the average of it.</p>