April 2011 ACT Math Discussion

<p>@premed ACDB</p>

<p>@Konata There was no formula. You could’ve solved it with proportions, which you did.</p>

<p>Also, I solved the rectangle problem by doing (4x)(x) = 4x^2. I set that equal to 80 (the area), and got x = 4.47. So the longer length is 17.9.</p>

<p>Princeton Review tricked me into thinking that the first 20-30 math questions were painfully easy. I got hit with a hard (or medium) question right off the bat.</p>

<p>What was the answer to the arithmetic series question?</p>

<p>sbl i dont remember that rectangle problem can you describe it.</p>

<p>@JNeemz It’s described a lot in the past few pages. I believe it has something to do with a new rectangle having a 4:1 ratio with the old rectangle of an area of 80, and it asks you to find the longer length of the new rectangle.</p>

<p>@Stanford Wasn’t that the problem where you had to find how many numbers were between X and Y? I got 8. Just wrote them out.</p>

<p>^Did you include X and Y? (In your counting)</p>

<p>pretty sure the arithmetic one was 7.</p>

<p>what were the options for the 80 area one? were 16 and 18 both options?</p>

<p>It was 7 10charrrr</p>

<p>Yeah I put 7.</p>

<p>Because it said exclusive so you don’t count X and Y.</p>

<p>I’m sorry some of you are just slowww. Really forgetting SOH CAH TOA? All you had to do for triangle graph problem was split the triangle into two seperate parts to turn it into a right triangle and use tangent and solve. Keep up or get left behind.</p>

<p>No need to be an ass hole about it, but yes that was a common strategy.</p>

<p>12mcgrawm- I think 95% of 11th-12th graders (esp on CC) know how to make 2 right triangles out of one triangle.</p>

<p>What about the arc question? I remember that the A and E included a Pie in the anwser…Can you guys help me with that prob?</p>

<p>Was 8 an option? I remember it was exclusive. I thought the answer choices for that were like 6, 8, 20.</p>

<p>the arc question was 24 i think it was C or H</p>

<p>What formula was used for the arc prob?</p>

<p>(144/360)(circumference)</p>

<p>@Aman If you’re referring to the circle with a circumference of 60, you don’t need a formula. You know there are 360* in a circle, and it gave you an arc of 144* and the circumference of 60. You could use proportions to solve it - 144/360 = x/60.</p>

<p>o0oooooooooo i got it! Thanks</p>

<p>What was the answer to the arc question? I got like 24 or something.</p>