BB2 Math - pg 717 #17,18

<p>Please look and help.</p>

<p>17</p>

<p>Vertices = the spots at the topmost and bottommost of the figure, not including V. Count them, they make 11.</p>

<p>Now draw lines going from each vertex to V. The ones that are the same as the edge do not count. Draw and count, you will get 8.</p>

<p>18</p>

<p>First, find the width of the rectangle. A is at -1/2 and D is at 1/2 and the midpoint is 0. Obviously, the length is one.</p>

<p>We were told that the area is 4. 4/1 = 4, so CD (y length) = 4. Naturally, d = -2 = a and c = 2 = b.</p>

<p>Put this in the equation y = px^3, let’s take A. -1/2^3 = -0.125. y = -2. So,</p>

<p>-2 = -0.125p.</p>

<p>Divide both sides by -0.125 to get 16.</p>

<p>wait, how do you know its -2 and 2. How do you know their evenly distant from the x axis?</p>

<p>Look at the figure. It’s obviously evenly distant.</p>

<p>If it weren’t, do you know how ridiculous the question would be?</p>

<p>EDIT: And I guess it’s also because A and C are equally distant from the x axis, because if let’s say C was 1.8, it wouldn’t have been a perfect rectangle. Try it if you don’t believe me.</p>

<p>I wasn’t saying your wrong, just needed to know for my own understanding.</p>

<p>You cant just look at it and say its even, especially when ti says Figure not drawn to scale. Can someone verify?</p>

<p>You can’t just assume d = -2 and c = 2: the figure is not to scale, so you can’t rely on how the figure looks.</p>

<p>The area is 4, the width is 1, so the length of the rectangle is 4. The length is also c - d = c - a since d = a.</p>

<p>The curve goes through points A and C, so c = p * (1/2)^3 = p/8, and a = p * (-1/2)^3 = -p/8, so c - a = p / 4 = 4 and p = 16.</p>

<p>Yea, thats it. </p>

<p>Ty dude.</p>