<p>I don’t get this problem. </p>
<li>Which of the following is equivalent to h(m + 1)</li>
</ol>
<p>A. g(m)
B. g(m) + 1
C. g(m) -1
D. h(m) + 1
E. h(m) - 1</p>
<p>Help would be great. Thanks</p>
<p>What is g(m)? Is there a graph that goes along with the problem?</p>
<p>Oh dang...I'm so stupid I can't believe I missed this.</p>
<p>It says questions 13-14 refer to the following functions g and h
g(n) = n^2 + n
h(n) = n^2 - n</p>
<p>No wonder I was like ***, I missed that part. Anyways I think I can do it now.</p>
<p>Alright then.</p>
<p>I need help with the question...I wasn't able to do 13..</p>
<p>What is 13? I don't have the blue book since I'm in college lol.</p>
<p>For 14 just sub in m+1 for every n you see in h, so you get
(m+1)^2-(m+1)=m^2+2m+1-m-1=m^2+m, so it appears that g(m) is the answer</p>
<p>The graphs g(x) = x^2 + x and h(x) = x^2 – x are basic parabolas with their roots respectively {-1, 0} and {0, 1}.
h(x+1) is h(x) shifted by 1 to the left, and it's exactly g(x).
h(x+1) and g(x) are equivalent,
and so are h(m+1) and g(m).</p>
<p>You could also rule out B, C, D, and E answers since they all are vertical shifts.</p>
<p>A question like this would be best done when you plug in...</p>
<p>For example lets plug in the answer 2 for m</p>
<p>g(n) = n^2 + n
h(n) = n^2 - n</p>
<p>g(n) = 2^2 + 2 = 6
h(n) = 2^2 - 2 = 2</p>
<p>h(m+1) with 2 as the variable = H(3)</p>
<p>h(3) = 3^2 - 3 = 9 - 3 = 6.</p>
<p>This leads you back to g(m) as m is still 2, it was just h(3) because of the h(m+1) so 6 definitely works. Now you can go through the other choices</p>
<p>A. g(m) = g(2) = 6 --> correct
B. g(m) + 1 = g(2) +1 = 7 --> wrong
C. g(m) -1 = g(2) -1 = 5 --> wrong
D. h(m) + 1 = h(2) + 1 = 3 --> wrong
E. h(m) - 1 = h(2) -1 = 1 --> wrong</p>
<p>Thus A is correct</p>
<p>Can some1 explain 13 2 me..</p>
<p>give the question</p>