<p>International students get form B. And I think they’re graded on the same curve, not sure though. Do you think Form B was easier? AB or BC?</p>
<p>I think form b of ab looks easier than form a. That might just be my bias from taking form a, but I know how to set up all of the problems (haven’t worked any out yet).</p>
<p>Form A was really easy…</p>
<p>Yeah, I get you think that. I don’t think it was hard, I just never learned how to do a few of the things it asked. I’ll work it out again now to see how I actually did. :)</p>
<p>Took AB, and now looking at form B, I’m happy I got form A</p>
<p>Lol I am from Canada and I got Form A, am I not an International student then?</p>
<p>But yeah glad I took Form A even though question 6 was a bite in the ass…I had no idea how to do midpoint approximation lol</p>
<p>
You don’t need to say that it twenty times. We get it.</p>
<p>im from bermuda, i took form A.</p>
<p>anyone want to work out the answers?</p>
<p>Can someone solve the FRQs and show all the work? Also, how much work/explanation do the graders want to see?</p>
<p>The Calc teachers in our school have tests with only multiple choice questions.</p>
<p>anyone had fun taking the ab exam lol i kinda liked it :P</p>
<p>Whoever works out the solutions is my hero.</p>
<p>^ For which one?</p>
<p>if anyone wants to work out BC form A, so i can see how miserably i failed, that would be awesome.</p>
<p>preferably all of them with solutions 
would be great! everyone would appreciate it!</p>
<p>I was referring to AB Form A in my original post about working out solutions.</p>
<p>Jersey, maybe you can help since you found the test so easy.</p>
<p>I already offered my assistance…
I’ll reiterate, which one would you like me to help you with?</p>
<p>preferably all of the answers :)</p>
<p>It’d be easier for me if you had a specific question</p>
<p>I feel really bad after taking this test…but whatever.
BC answers:</p>
<p>1a) integral from 0 to 6, f(t)dt
b) f(8) - 108 haha probably wrong
c) 0 for 0<t<6
integral from 6 to t of 125 for 6<t<7
(integral from 6 to 7 of 125 for 6<t<7) +(integral from 7 to t of 108 for 7<t<9)
d) (integral from 0 to 9 f(t)dt) - (integral from 6 to 7 of 125 for 6<t<7) +(integral from 7 to 9 of 108 for 7<t<9)</p>
<p>2a) secant line of (5,13) and (7,21)
b) i don’t feel like writing this.
c) trapezoidal sum from b) minus integral from 8 to 12 of P(t)
d) set P(t) equal to 0 and found maximum.</p>
<p>3a) plugged 3 in for dy/dx (?)
b) arclength formula: integral from 0 to 4 of the sqrt of (dx/dt)^2 + (dy/dt)^2
c) i forget. haha it was probably ****ty though.
d) i. set x(t) equal to 5
ii. plug values of t into (dy/dx)
iii. I don’t think I had time to finish this, but I knew how to do it </p>
<p>4a) integral from 0 to 9 of (6 - 2rt(x))dx
b) pi*integral from 0 to 6 of {(7-2rt(x))^2 - 1}dx
c) I don’t feel like doing this…</p>
<p>5a) I remember I got -1.25
b) 1/3 (L’Hopital’s Rule)
c) I don’t remember. Probably screwed it up though…</p>
<p>6) ■■■.</p>
<p>Well there you go. Tell me if I failed?</p>